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Flura [38]
3 years ago
7

*Brainliest* What is the domain of the function shown in thr table?

Mathematics
2 answers:
larisa86 [58]3 years ago
5 0

Answer:

Domain is { 3,5,7,9}

Step-by-step explanation:

The domain is the input values

Domain is { 3,5,7,9}

kaheart [24]3 years ago
5 0

Answer:

Domain - {3, 5, 7, 9} (B)

Step-by-step explanation:

Domain - imput values, X values

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32. Which of the following is horizontal ellipse
maria [59]

Answer:

  • b. 16x² + 25y² = 1

Step-by-step explanation:

Only one of them has a < b in ax² + by² = c formula, making its graph horizontal

All the rest are vertical, see attached

6 0
3 years ago
Hence factorize completely the expression<br>9x³y² - 4xy⁴​
Aloiza [94]

Step-by-step explanation:

9 {x}^{3} {y}^{2}  - 4x {y}^{4}  \\  = x {y}^{2} (9 {x}^{2}  - 4 {y}^{2} )

4 0
3 years ago
The value 5 is an upper bound for the zeros of the function shown below.
Mice21 [21]

Answer:

The given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

Step-by-step explanation:

Given

f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18

We know the rational zeros theorem such as:

if x=c is a zero of the function f(x),

then f(c) = 0.

As the f\left(x\right)\:=\:x^2\:+\:x^3\:-\:11x^2\:-\:9x\:+\:18 is a polynomial of degree 4, hence it can not have more than 4 real zeros.

Let us put certain values in the function,

f(5) = 448, f(4) = 126, f(3) = 0, f(2) = -20,

f(1) = 0, f(0) = 18, f(-1) = 16, f(-2) = 0, f(-3) = 0

From the above calculation results, we determined that 4 zeros as

x = -3, -2, 1, and 3.

Hence, we can check that

f(x) = (x+3)(x+2)(x-1)(x-3)

Observe that,

for x > 3, f(x) increases rapidly, so there will be no zeros for x>3.

Therefore, the given statement that value 5 is an upper bound for the zeros of the function f(x) = x⁴ + x³ - 11x² - 9x + 18  will be true.

5 0
3 years ago
Please help.<br> Is algebra.
Readme [11.4K]

Answer to question 1 is D

answer to question 2 is A

5 0
2 years ago
149 cars are waiting to take a ferry across the channel. Each ferry can only hold 18 cars. How many cars will be on the last fer
balandron [24]

149 \div 18 = x
8r5 = x
There will be 9 trips the ferry makes and on the last trip there will be 5 cars on the ferry.

5 0
3 years ago
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