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Readme [11.4K]
3 years ago
6

How do you prove this using a two-column proof format?

Mathematics
1 answer:
Law Incorporation [45]3 years ago
8 0

I'm not sure if you need the answer or just the steps to start, so I will just give u the steps. First, just take a step back and take it one step at a time. Once you have an idea of how the two triangles are congruent, make 2 columns, one with statements and one with reasons. On the statements side, put given information and what you learn along the way, like if it is given x=y, and y=z, then what you can put down after that is x=z. On the reasons side, put the properties or formulas you used to reach your solution. For instance, if x=y and y=z, x=z by the Transitive property of equality. Proofs are time consuming, tedious and utterly frustrating. Just take it slowly and you will be fine.

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3/4 as a decimal is .75
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What does 100 × 30% equal I'm a bit confused
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4 0
3 years ago
P³ = 1/8 please help me if anybody can .
ivanzaharov [21]

Answer:

p= \dfrac{1}{2}

Step-by-step explanation:

Given equation:

p^3=\dfrac{1}{8}

Cube root both sides:

\implies \sqrt[3]{p^3}= \sqrt[3]{\dfrac{1}{8}}

\implies p= \sqrt[3]{\dfrac{1}{8}}

\textsf{Apply exponent rule} \quad \sqrt[n]{a}=a^{\frac{1}{n}}:

\implies p= \left(\dfrac{1}{8}\right)^{\frac{1}{3}}

\textsf{Apply exponent rule} \quad \left(\dfrac{a}{b}\right)^c=\dfrac{a^c}{b^c}:

\implies p= \dfrac{1^{\frac{1}{3}}}{8^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad 1^a=1:

\implies p= \dfrac{1}{8^{\frac{1}{3}}}

Rewrite 8 as 2³:

\implies p= \dfrac{1}{(2^3)^{\frac{1}{3}}}

\textsf{Apply exponent rule} \quad (a^b)^c=a^{bc}:

\implies p= \dfrac{1}{2^{(3 \cdot \frac{1}{3})}}

Simplify:

\implies p= \dfrac{1}{2^{\frac{3}{3}}}

\implies p= \dfrac{1}{2^{1}}

\implies p= \dfrac{1}{2}

3 0
1 year ago
Read 2 more answers
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