Consider the markings on the triangles. Which congruence theorem could be used to prove that the two triangles are congruent? Ex
1 answer:
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DECA=10, decagon = 10 sides.
since each side is 1.8 long, all 10 sides will be 10*1.8 or 18 units long, so that'd be the perimeter then,
since each side is 1.8 long, all 10 sides will be 10*1.8 or 18 units long, so that'd be the perimeter then,
Answer:
Slope of required line if both lines are parallel: y=4x-20
Slope of required line if both lines are perpendicular: y=-1/4x+14
Step-by-step explanation:
We need to find equation of line while we are given another line having equation y=4x-6 and passes through point (8,12)
<u><em>Note: Since it is not given if the required line is parallel or perpendicular to the given line. I will solve for both cases.</em></u>
If Both lines are parallel the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are parallel there slopes are same
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=4
Now finding y-intercept
Using slope m=4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=-20
Equation of required line having slope m=4 and y-intercept b=-20 is
If Both lines are perpendicular the equation of new line will be:
We need to find slope and y-intercept to write equation of new line.
When lines are perpendicular there slopes are opposite of each other
So, slope of given line y=4x-6 is 4 (Compare with general equation y=mx+b, m is slope so m=4)
Slope of new line is: m=-1/4
Now finding y-intercept
Using slope m=-1/4 and point (8,12) we can find y-intercept
y-intercept of new line is: b=14
Equation of required line having slope m=-1/4 and y-intercept b=14 is