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3 years ago

Y=2x + 4 y = 2(x + 2) what is x

Mathematics

1 answer:

Oxana [17]3 years ago

4 0

Answer:

I believe 1.) is x=y-4/2 and 2.) x=y-4/2 as well

Step-by-step explanation:

1.)

y=2x+4

-subtract 4 on both sides-

y-4=2x

-divide 2 on both sides-

x=y-4/2

2.)

y=2(x+2)

-distribute the 2-

y=2x+2

-subtract 2 on both sides-

y-2=2x

-divide 2 on both sides-

x=y-2/4

I dont know exactly if this is correct, but i hope it helps! :)

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SURFACE OF AREA OF PRISMS (please help)

Anton [14]

Answer:

Step-by-step explanation:

SA=2(LW+LH+WH)

SA=2(5+4+3)

SA=2(12)

SA=24

SA=bH+2LS+bL

SA=4+2x7+8

SA=4+14+8

SA=25

SA=2(LW+LH+WH)

SA=2(13+17+2)

SA=2x32

SA=64

(the rest of the shapes

i can't see but you can use that formula to do it <3 GL!)

3 0

3 years ago

Select the correct answer from each drop-down menu.

il63 [147K]

Answer:

Find below correct question:

When she was 20, liz started saving $6,000 a year for retirement. her goal is to reach & 100,00 in savings by the time she’s 30. her account earns 8% interest per year, compounded annually. liz (will/ won’t) have saved $100,000 by age 30. she’ll (exceed/ fall short of) her goal by about ($10,081/ $13,081/ $14,011)

liz won’t have saved $100,000 by age 30. she’ll fall short of her goal by about $13,081

Step-by-step explanation:

First and foremost we need to know the worth of Liz's retirement savings when she is 30 using excel fv formula as follows:

=fv(rate,nper,-pmt,pv)

rate is the interest earned per year which is 8%

nper is the duration of savings which is 10 years

pmt is the amount of yearly savings which is $6,000

pv is the present worth of total savings which is not known

=fv(8%,10,-6000,0)=$86,919.37

Hence,Liz would be not be able to reach $100,000 at age 30.

Shortfall=$100,000-$86,919.37 =$ 13,080.63

5 0

4 years ago

Ion need the work js gimme the answer thanks

defon

D because you are finding the difference

4 0

3 years ago

Read 2 more answers

Im giving away free points, your welcome

goblinko [34]

Thanks :D shdjsbsusnhsidbshsjs

8 0

4 years ago

Read 2 more answers

One 8.3 ounce can of Red Bull contains energy in two forms: 27 grams of sugar and 80 milligrams of caffeine. One 23.5 ounce can

bulgar [2K]

Answer:

41) 2 Red Bull and 1 Jolt Cola

42) 1 Red Bull and 3 Jolt Cola

43) 2 Red Bull and 2 Jolt Cola

44) 3 Red Bull and 4 Jolt Cola

Determine the number of cans of each drink that when combined will contain 403 grams sugar and 1200 milligrams caffeine: 1 Red Bull and 4 Jolt Cola

Step-by-step explanation:

Let X be the cans of Red Bull.

Let Y be the cans of Jolt Cola.

41)

One can of Red Bull has 27g of sugar. One can of Jolt cola has 94g of sugar. So we have the equation:

X(27)+Y(94)=148...(1)

One can of Red Bull has 80mg of caffeine. One can of Jolt cola has 280mg of caffeine. So we have the equation:

X(80)+Y(280)=440...(2)

We find the answear by solving the system of equations:

27X+94Y=148...(1)

80X+280Y=440...(2)

Solving the system:

27X+94Y=148...(1)

27X=148-94Y

X=148/27 -(94/27)Y

Substituting X in (2)

80X+280Y=440...(2)

80[148/27 -(94/27)Y]+280Y=440

(11840/27)-(7520/27)Y+280Y=440

(11840/27)+(40/27)Y=440

(40/27)Y=440-(11840/27)

(40/27)Y=40/27

Y=1

Substituting Y in (1)

27X+94Y=148...(1)

27X+94(1)=148

27X+94=148

27X=148-94

X=54/27

X=2

So we need 2 cans of Red Bull and 1 of Jolt Cola to get 148g of sugar and 440mg of caffeine.

42) Following the same steps we have:

27X+94Y=309...(1)

80X+280Y=920...(2)

Solving the system:

27X+94Y=309...(1)

27X=309-94Y

X=309/27 -(94/27)Y

Substituting X in (2)

80X+280Y=920...(2)

80[309/27 -(94/27)Y]+280Y=920

(24720/27)-(7520/27)Y+280Y=920

(24720/27)+(40/27)Y=920

(40/27)Y=920-(24720/27)

(40/27)Y=40/9

Y=3

Substituting Y in (1)

27X+94Y=309...(1)

27X+94(3)=309

27X+282=309

27X=27

X=1

So we need 1 can of Red Bull and 3 of Jolt Cola to get 309g of sugar and 920mg of caffeine.

43) Following the same steps we have:

27X+94Y=242...(1)

80X+280Y=720...(2)

Solving the system:

27X+94Y=242...(1)

27X=242-94Y

X=242/27 -(94/27)Y

Substituting X in (2)

80X+280Y=720...(2)

80[242/27 -(94/27)Y]+280Y=720

(19360/27)-(7520/27)Y+280Y=720

(19360/27)+(40/27)Y=720

(40/27)Y=720-(19360/27)

(40/27)Y=80/27

Y=2

Substituting Y in (1)

27X+94(2)=242...(1)

27X+188=242

27X=54

X=2

So we need 2 can of Red Bull and 2 of Jolt Cola to get 242g of sugar and 720mg of caffeine.

43) Following the same steps we have:

27X+94Y=457...(1)

80X+280Y=1360...(2)

Solving the system:

27X+94Y=457...(1)

27X=457-94Y

X=457/27 -(94/27)Y

Substituting X in (2)

80X+280Y=1360...(2)

80[457/27 -(94/27)Y]+280Y=1360

(36560/27)-(7520/27)Y+280Y=1360

(36560/27)+(40/27)Y=1360

(40/27)Y=1360-36560/27

(40/27)Y=160/27

Y=4

Substituting Y in (1)

27X+94Y=457...(1)

27X+94(4)=457

27X+376=457

X=3

So we need 3 cans of Red Bull and 4 of Jolt Cola to get 457g of sugar and 1360mg of caffeine.

Determine the number of cans of each drink that when combined will contain 403 grams sugar and 1200 milligrams caffeine

Following the same steps we have:

27X+94Y=403...(1)

80X+280Y=1200...(2)

Solving the system:

27X+94Y=403...(1)

27X=403-94Y

X=403/27 -(94/27)Y

Substituting X in (2)

80X+280Y=1200...(2)

80[403/27 -(94/27)Y]+280Y=1200

(32240/27)-(7520/27)Y+280Y=1200

(32240/27)+(40/27)Y=1200

(40/27)Y=1200-(32240/27)

(40/27)Y=160/27

Y=4

Substituting Y in (1)

27X+94Y=403...(1)

27X+94(4)=403

27X=-94(4)+403

X=1

So we need 1 can of Red Bull and 4 of Jolt Cola to get 403g of sugar and 1200mg of caffeine.

4 0

4 years ago