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vazorg [7]
3 years ago
15

What is the best estimate for the square root of 15?

Mathematics
2 answers:
cupoosta [38]3 years ago
7 0
The Correct answer is B.
When you multiply each of the numbers by itself, 3.8729 would be the closest to 15
kondaur [170]3 years ago
4 0

Answer:

b

Step-by-step explanation:

3.87298334621

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I need the answer. Please help.
Marysya12 [62]

Using the Pythagorean theorem:

WY =√(5^2 + 12^2)

WY = √(25 +144)

WY = √169

WY = 13 mm

7 0
3 years ago
45/19 as a decimal rounded to the nearest tenth
Maslowich

Answer:

Step-by-step explanation:

45/19 ~ 2.4

Hope that helps!

8 0
3 years ago
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Y'all I need help with this !!!
Zanzabum

Answer:

see explanation

Step-by-step explanation:

The opposite angles of an inscribed quadrilateral are supplementary, thus

5x + 20 + 7x - 8 = 180

12x + 12 = 180 ( subtract 12 from both sides )

12x = 168 ( divide both sides by 12 )

x = 14

Thus

∠ RQP = 10x = 10(14) = 140°

∠PSR = 180° - 140° = 40° ( opposite angles are supplementary )

∠ SRQ = 7X - 8 = 7(14) - 8 = 98 - 8 = 90°

∠ QPS = 5x + 20 = 5(14) + 20 = 70 + 20 = 90°

6 0
3 years ago
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A figure is chosen from inside the blue region. Which statement about that figure is true?
lana [24]

Answer:

all 4 angles are congruent

Step-by-step explanation:

2 pairs of parallel sides.

4 right angles (90°).

Opposite sides are parallel and congruent.

All angles are congruent

6 0
3 years ago
The vertex of the parabola below is at the point (-4,-2) wich of the equations below could be the one for this parabola
MrRissso [65]

The parabola with with a vertex at (-4,-2) represents any member of parabolas with the equation y(x)=a(x+4)^2-2 where a is any real number with the exception that  a\neq 0.

The reason any equation  of the form y(x)=a(x+4)^2-2 works is that there are an infinite number of parabolas with a vertex at (-4,-2). All of these parabolas are formed by applying some transformation that involves a vertical translation of -2 and a horizontal translation of -4 on the parabola y=x^2. The different variations are archived by varying the constant a.  When a is negative, the parabolas will face downwards. When a is negative, the parabolas will be face downwards.

6 0
3 years ago
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