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alexira [117]
4 years ago
13

A-domain: positive integers; range: positive integers; No, it is not a function.

Mathematics
2 answers:
Vesna [10]4 years ago
7 0

Answer:

D

Step-by-step explanation:

The domain of a function is the span of x-values it covers, while the range of a function is the span of y-values it covers.

DOMAIN:

We can see that the graph covers <em>all </em>x-values to the right of x=-3.

However, <em>at exactly</em> x=-3, the graph goes upwards infinitely. So, we say that there is a <em>vertical asymptote</em> at x=-3. Therefore, x=-3 is <em>not</em> included in our domain.

So, our domain is only all values greater than -3.

As an inequality, this is:

x>-3

RANGE:

We can see that the graph covers all y-values until y=0.

At y=0, we have a horizontal asymptote.

Therefore, our y-values will <em>never</em> touch y=0.

So, our range are all values greater than 0.

In an inequality, this is:

y>0

To determine if a function is a function, we can use the vertical line test.

If we draw a vertical line anywhere on the graph, it should not cross the graph more than once.

We can see that no matter where we draw our vertical line, it will only cross the graph once. This may be hard to see with the vertical asymptote, but the vertical asymptote will <em>never</em> be completely vertical despite its name.

So, this is indeed a function.

The answer choices that reflects these answers is D.

So, our answer is D.

And we're done!

Nookie1986 [14]4 years ago
6 0

Answer: y>0

Step-by-step explanation:

Let's look at the graph. If we do the vertical line test, we can figure out that YES, it is a function, so option b and c are already out of the picture.

Now, to find the domain, look at the graph and shade it back to the x-axis. The domain includes every number greater than 3, so the domain is x>3.

To find the range, take a look at the graph and shade it back to the y-axis. The range includes every real number greater than 0, so the range is y>0

This means that d is the answer.

I really hope this helps!

Best wishes :)

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Andru [333]

1. Given the functions f(x) = log₂(5x)  and g(x) = 5ˣ - 2 only statement c is true

2. The solution of 3y² + 5y > -2 is a. x < –1 or x is greater than negative two thirds

<h3>1. How to find which statements are true. </h3>

Statement a

Since f(x) = log₂(5x) which is a logarithm function is undefined for (-∞, 0) and defined for (0, +∞) and g(x) = 5ˣ - 2 which is an exponential function is defined for (-∞, +∞).

Also, since f(x) is decreasing on the interval (0, 1/5) while g(x) decreases on the interval (-∞, 0). So, they have do not have a common interval on (0, 1).

So, statement a. Both f(x) and g(x) decrease on the interval of (–∞, 1).

is false

Statement b

Since f(x) = log₂(5x) which is a logarithm function is defined for (0, +∞)  and g(x) = 5ˣ - 2 which is an exponential function is defined for (-∞, +∞).

So, the statement b Both f(x) and g(x) have the same domain of (0, ∞) is false

Statement c

Since f(x) = log₂(5x) which is a logarithm function has a range of (0, +∞).  and g(x) = 5ˣ - 2 which is an exponential function is has a range of (-2, +∞).

So, they have a common interval of (0, +∞).

So, the statement c. Both f(x) and g(x) have a common range on the interval (–2, ∞) is true

Statement d

To find the x-intercept of f(x), we equate f(x) to zero.

So, f(x) = log₂(5x)

0 = log₂(5x)

2⁰ = 5x

1 = 5x

x = 1/5

To find the x-intercept of g(x), we equate g(x) to zero.

g(x) = 5ˣ - 2

0 = 5ˣ - 2

2 = 5ˣ

x = ㏒₅2

Since the x-intercept of f(x) = 1/5 and the x- intercept of g(x) = ㏒₅2. So, they do not have a common x - intercept.

So, the statement d. Both f(x) and g(x) have the same x-intercept of (1, 0) is false.

So, only statement c is true

<h3>2. How to find the solution of 3y² + 5y > -2?</h3>

3y² + 5y > -2

3y² + 5y + 2 > 0

3y² + 3y + 2y + 2 > 0

3y(y + 1) + 2(y + 1) > 0

(3y + 2)(y + 1) > 0

So, the boundary values are at

(3y + 2)(y + 1) = 0

(3y + 2) = 0 or (y + 1) = 0

y = -2/3 or y = -1

So, we require (3y + 2)(y + 1) > 0

For y < -1 say -2, (3y + 2)(y + 1) = (3(-2) + 2)((-2) + 1)

= (-6 + 2)(-2 + 1)

= -4(-1)

= 4 > 0

For -1 < y < -2/3 say -1/3, (3y + 2)(y + 1) = (3(-1/3) + 2)((-1/3) + 1)

= (-1 + 2)(-1 +3)/2

= 1(-2/2)

= -1 < 0

For y > -2/3 say 0, (3y + 2)(y + 1) = (3(0) + 2)((0) + 1)

= (0 + 2)(0 + 1)

= 2(1)

= 2 > 0

So, for (3y + 2)(y + 1) > 0, y < -1 or y > -2/3

So, the solution of 3y² + 5y > -2 is a. x < –1 or x is greater than negative two thirds

Learn more about logarithm and exponential function here:

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2 years ago
Avalanches occur at 245 miles per hour. 245 miles per hour is 4 times faster than the fastest downhill skier. What is the speed
Lynna [10]

Answer:

61

Step-by-step explanation:

Since we now that avalanches occur at 245 mph and that is 4 times as fast as a skier. So we can divide 245/4  = 61.25 ≈61

Hope This Helps!

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8 0
4 years ago
???????????????????? thanks for answering it
Klio2033 [76]

Answer:

A

Step-by-step explanation:

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