Answer:
2.447 × 10⁴ years
Explanation:
Step 1: Given data
- Half-life of the radioactive atom (t1/2): 3,500 years
- Parent-daughter ratio ([A]/[A]₀): 1:127 (1/127)
Step 2: Calculate the rate constant
Radioactive decay follows first-order kinetics. We can calculate the rate constant (k) using the following equation.
k = ln2 / (t1/2) = ln2 / 3,500 y = 1.980 × 10⁻⁴ y⁻¹
Step 3: Calculate the time elapsed (t)
For first-order kinetics, we will use the following expression.
ln ([A]/[A]₀) = -k × t
t = ln ([A]/[A]₀)/ (-k)
t = ln (1/127) / (1.980 × 10⁻⁴ y⁻¹) = 2.447 × 10⁴ y
Germ cells are also diploid, but they are found only in the gonads. Gonads are the ovaries in females and testes in males. <span>Gametes are </span>haploid cells<span>, which means that they have only one set of chromosomes. </span>
Insecticide or a pesticide I believe.
Answer:
7 % progeny will show wild type phenotype
Explanation:
Parent 1: Normal wings and small eyes : DDee
Parent 2 : Downward wings and normal eyes : ddEE
DDee X ddEE = DdEe ( All have normal wings and normal eyes )
When a F1 individual is test crossed:
DdEe X ddee =
De/de = Parental
dE/de = Parental
DE/de = Recombinant
de/de = Recombinant
Recombination frequency between the two genes is 14% hence DE/de and de/de will each have 7% frequency. Since DE/de ( DdEe ) will give wild type phenotype, it means that 7% progeny will have wild type phenotype.
Answer:
AAG
Explanation:
is the silent one in this case
