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MrRissso [65]
3 years ago
14

Find the length of the hypotenuse of a right triangle if a = 9 and b = 12.

Mathematics
2 answers:
emmainna [20.7K]3 years ago
8 0
C^2=a^2+b^2
c=√(9^2+12^2)
c=15
The correct answer is B
tino4ka555 [31]3 years ago
6 0
15 is the answer of this question
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Write an equation for the line perpendicular to y=1/3x-2 and passing through the point (3,3)
maria [59]

line given slope = x coefficient = 1/3

Perpendicular slopes must be opposite reciprocals of each other:  m1 * m2 = –1

line slope (m) = -3

line equation formula = y = mx + b

y = -3x + b

from the point given

x = 3

y= 3

3 = -9 + b

b = 12

y = -3x + 12

6 0
2 years ago
What is the volume of a figure that is 9 inches wide, 3 inches tall and 3 inches long?
motikmotik

Answer:

1/2

Step-by-step explanation:

1/2 of an answer is zero answer

5 0
3 years ago
PLS HELP GIVING 11 POINTS
Svetradugi [14.3K]

Answer:

3. 40 4. 132

Step-by-step explanation:

you multiply the length and the width

8 0
1 year ago
Read 2 more answers
Area of a regular hexagon with an apothem of 15 cm
Anton [14]

Answer:

area = 779.4 cm²

Step-by-step explanation:

divide it into 6 equal equilateral triangles. Each corner of a triangle will be 60°.

tan 60° = 15/x

1.7321 = 15/x

x = 8.66 (this is one-half of the base of the triangle)

base = 17.32 cm

area of one triangle = 1/2(17.32)(15) = 129.9 cm²

129.9(6) = 779.4 cm²   (because 6 triangles make up the hexagon)

8 0
2 years ago
Help
kykrilka [37]

Let n =  the hours elapsed when the two trains are 660 miles apart.


Let the first train travel east and the second train travel west.

The distance traveled by the first train is

x = (50 mi/h)*(n h) = 50n mi


The distance traveled by the second train is

y = (60 mi/h)*(n h) = 60n h


The distance between the two trains after n hours is

x + y = 50 n + 60n = 110n mi


Because this distance is 660 miles, therefore

110n = 660

n = 6 hours


Answer: 6 hours


I hope this helps. Sorry it took so long

3 0
3 years ago
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