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3 years ago

13

a supplier sells 2 1/4 pounds of mulch for every 1 1/3 pounds of gravel. The supplier sells 172 pounds of mulch and gravel combi

ned. how many pounds of each item did the supplier sell?

1 answer:

astraxan [27]3 years ago

3 0

2 1/4=2 3/12 and 1 1/3= 1 4/12

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What is the area in square units of the rectangle

Vsevolod [243]

$\bf \textit{area of a rectangle}\\\\
A=length\cdot width\qquad \qquad A=\cfrac{3}{7}\cdot \cfrac{2}{9}\implies A=\cfrac{6}{63}\implies A=\cfrac{2}{21}$

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3 years ago

If you start with 60% sunny days and after 200 days it decrease by 50%. How many days of the 200 were sunny days

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120 sunny days if there were 60% of em in 200 days

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2 years ago

Cuales son los terminos que siguen en cada sucesion:a)2,4,8,16,32,64,....B)1,3,5,7,9,....C)1,3,6,10,15,21,28,36,45

Elanso [62]

Answer:

a) Número siguiente = Número anterior * 2

b) Número siguiente = Número anterior + 2

c) Número siguiente = Número anterior + (n + 1)

Step-by-step explanation:

a) Para la secuencia 2,4,8,16,32,64, ....

El siguiente número es dos veces el número anterior.

Por ejemplo, 4 = 2 * 2, 8 = 4 * 2, 16 = 8 * 2 etc.

b) Para la secuencia 1,3,5,7,9, ....

El siguiente número es igual al número anterior + 2

Por ejemplo, 3 = 1 + 2, 5 = 3 + 2, 7 = 5 + 2 etc.

c) Para la secuencia1,3, 6,10,15,21,28,36,45

La diferencia entre los números aumenta en +1.

3-1 = 2

6-3 = 3

10-6 = 4

15-10 = 5

21-15 = 6

28-21 = 7

3 0

2 years ago

The comprehensive strength of concrete is normally distributed with μ = 2500 psi and σ = 50 psi. Find the probability that a ran

VARVARA [1.3K]

Answer:

The probability that the diameter falls in the interval from 2499 psi to 2510 psi is 0.00798.

Step-by-step explanation:

Let's define the random variable, $X =$ "Comprehensive strength of concrete". We have information that $X$ is normally distributed with a mean of 2500 psi and a standard deviation of 50 psi (or a variance of 2500 psi). In other words, $X \sim N(2500, 2500)$ .

We want to know the probability of the mean of X or $\bar{X}$ that falls in the interval $[2499;2510]$ . From inference theory we know that :

$\bar{X} \sim N(2500, \frac{2500}{5}) \Rightarrow \bar{X} \sim N(2500,500)$

Now we can find the probability as follows:

$P(2499 \leq \bar{X} \leq 2510) \Rightarrow P(\frac{2499 - 2500}{500} \leq \frac{\bar{X} - 2500}{500} \leq \frac{2499 - 2500}{500} ) \Rightarrow\\\Rightarrow P(-0.002 \leq \frac{\bar{X} - 2500}{500} \leq 0.02 ) \Rightarrow P(-0.002 \leq Z \leq 0.02 )$

Where $Z \sim N(0,1)$ , then:

$P(-0.002 \leq Z \leq 0.02 ) \approx P(0 \leq Z \leq 0.02 ) = P(Z \leq 0.02 ) - P(Z \leq 0) \\P(0 \leq Z \leq 0.02 ) = 0.50798 - 0.5 = 0.00798$

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3 years ago

Y = (x + 4)2 - 1<br> Standard form

denpristay [2]

answer :

y = 2x + 7

i hope it helped

3 0

2 years ago

Read 2 more answers