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3 years ago

Solve for x. The polygons are similar

Mathematics

1 answer:

kotykmax [81]3 years ago

4 0

$\frac{8x-2}{42}=\frac{63}{49}\\\frac{8x-2}{42}=\frac{9}{7}\\7(8x-2)=9\cdot42\ /:7\\8x-2=9\cdot6\\8x-2=54\\8x=54+2\\8x=56\ /:8\\x=7$

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The perimeter of the rectangle is 48 inches. If the width of the rectangle is 11 inches what is the length?

sukhopar [10]

Answer:

The length is 13 inches.

Step-by-step explanation:

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3 years ago

What's the answer of 13846+8273636-3763x8273736

ipn [44]

13846+8273636
= 8287482

8287482-3763
=8283719

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3 years ago

Which is true about the domain and range of each function

Igoryamba

Answer:

the range of a function is the set of results solutions or output values (y)to the equation for a given input. to be honest a function only has one result for each domain.

Step-by-step explanation:

R there answer choices?

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2 years ago

Factor the expression <br><br> by filling in the blank

inna [77]

Answer:

After factoring we get:

$(\mathbf{2}q^2r+\mathbf{3}s^2t)(\mathbf{4}q^4r^2-\mathbf{6}q^2rs^2t+\mathbf{9}s^4t^2)$

Step-by-step explanation:

The expression given is:

$8q^6r^3+27s^6t^3$

We need to factor the expression using the formula:

$a^3+b^3=(a+b)(a^2-ab+b^2)$

Given the expression:

we have

$a = 2q^2r\\b= 3s^2t$

Now applying the formula: $a^3+b^3=(a+b)(a^2-ab+b^2)$

$(2q^2r)^3+(3s^2t)^3\\=(2q^2r+3s^2t)((2q^2r)^2-(2q^2r)(3s^2t)+(3s^2t)^2)\\=(2q^2r+3s^2t)(4q^4r^2-6q^2rs^2t+9s^4t^2)$

So, after factoring we get:

$(\mathbf{2}q^2r+\mathbf{3}s^2t)(\mathbf{4}q^4r^2-\mathbf{6}q^2rs^2t+\mathbf{9}s^4t^2)$

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2 years ago

Simplify (2x + 5y)(3x – 7y) - 2xy<br> Helpppp

storchak [24]

If you want a faster way to get these things solved, use the math papa algebra calculator

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3 years ago