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3 years ago

6

12^2=17x+5 show the work

1 answer:

alexdok [17]3 years ago

5 0

Simplify 12^2 to 144

144 = 17x + 5

Subtract 5 from both sides

144 - 5 = 17x

Simplify 144 - 5 to 139

139 = 17x

Divide both sides by 17

139/17 = x

Switch sides

<u>x = 139/17</u>

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Pleaseee answer correctly !!!!!!!!!!! Will mark Brianliest !!!!!!!!!!!!!!!!!!

tester [92]

Answer:

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Step-by-step explanation:

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3 years ago

A quadratic function and an exponential function are graphed below. How do the decay rates of the functions compareover the inte

Kobotan [32]

To check the decay rate, we need to check the variation in y-axis.

Since our interval is

$-2We need to evaluate both function at those limits.At x = -2, we have a value of 4 for both of them, at x = 0 we have 1 for the exponential function and 0 to the quadratic function. Let's call the exponential f(x), and the quadratic g(x).[tex]\begin{gathered} f(-2)=g(-2)=4 \\ f(0)=1 \\ g(0)=0 \end{gathered}$

To compare the decay rates we need to check the variation on the y-axis of both functions.

$\begin{gathered} \Delta y_1=f(-2)-f(0)=4-1=3 \\ \Delta y_2=g(-2)-g(0)=4-0=4 \end{gathered}$

Now, we calculate their ratio to find how they compare:

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1 year ago

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3 years ago

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Find the surface area of this triangular prism.

vesna_86 [32]

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Step-by-step explanation:

A=Area

Using the formulas

$A= 2A_{b} +(a+b+c)h\\A_{b} = \sqrt{s(s-8)(s-10)(s-6)} \\s= \frac{8+10+6}{2}$

Solving for A

$A=ah+bh+ch+\frac{1}{2}*\sqrt{-a^4+2(ab)^2+2(ac)^2-b^4+2(bc)^2-c^4}$

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3 years ago

Find x<br> 5[x^2]+5[x]-x^2-x=2004

a_sh-v [17]

The answer is either $x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

To solve: Let's solve your equation step-by-step.

5x2+5x−x2−x=2004

Step 1: Simplify both sides of the equation.

4x2+4x=2004

Step 2: Subtract 2004 from both sides.

4x2+4x−2004=2004−2004

4x2+4x−2004=0

Step 3: Use quadratic formula with a=4, b=4, c=-2004.

x= −b±√b2−4ac /2a

x= −4±√32080 /8

$x=\frac{-1}{2}+\frac{1}{2}\sqrt{2005}\\$ or $x=\frac{-1}{2}+\frac{-1}{2}\sqrt{2005}$

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3 years ago

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