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2 years ago

Is it enough to plot two points to see a pattern for a graph ? Explain.

2 answers:

7 0

It all depends on what the objective of your graph is, although it is better to be safe then sorry...so if you can plot as many points as you can, it won't hurt.

devlian [24]2 years ago

6 0

No, the least amount of points you can do on a graph to see the pattern is 3 because than you can get a better line for your graph to see what kind of pattern your graph is.

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The sale price of a bike is $189.50. The sale tax is 5%. What is the total price?

Roman55 [17]

It would be $947.50 because you would multiply $189.50 by 0.05.

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3 years ago

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Which is better 4:3 odds or 3:4 odds? Why?

juin [17]

Answer:

no problem?

Step-by-step explanation:

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3 years ago

Find two numbers witha sum of 20 and a difference of 14

bixtya [17]

from the given equation

X+Y=20-->i

X-Y=14--->ii

add eq i and eq ii

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x=17

putting the value of x=17 in eq i

17+y=20

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3 years ago

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3 years ago

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A square napkin is folded in half on the diagonal and placed on the diameter of a round plate (see diagram below). If the folded

Crank

Answer:

$A=81(\pi-1)\ in^2$

Step-by-step explanation:

step 1

Find the area of the plate

The area of a circle is given by the formula

$A=\pi r^{2}$

we have

$r=18/2=9\ in$ ---> the radius is half the diameter

substitute

$A=\pi (9)^{2}\\A=81\pi\ in^2$

step 2

Find the area of the square napkin folded (is a half of the area of the square napkin)

we know that

The diagonal of the square is the same that the diameter of the plate

Applying Pythagorean theorem

$D^2=2b^2$

where

b is the length side of the square

we have

$D=18\ in$

substitute

$18^2=2b^2$

solve for b^2

$b^2=162\ in^2$ -----> is the area of the square

Divide by 2

$162/2=81\ in^2$

step 3

Find the area of the space on the plate that is NOT covered by the napkin

we know that

The area of the space on the plate that is NOT covered by the napkin, is equal to subtract the area of the square napkin folded (is a half of the area of the square napkin) from the area of the plate

$A=(81\pi-81)\ in^2$

simplify

$A=81(\pi-1)\ in^2$

8 0

3 years ago