Answer:
b. laminar flow
the reynold number is 1329.26
Explanation:
Re = (V x D x ρ)/ η
where,
V = mean velocity = 15.9 cm/s = 0.159m/s
D = vessel diameter = 2.15cm = 0.0215m
ρ = blood density = 1050 kg/m3 = 0.00105 kg/cm3
η = dynamic viscousity= 2.70 × 10-3 Pa·s = 2.70 × 10-3 kg/m-s
applying the formular to calculate for reynolds number, Re =
Re = (V x D x ρ)/ η
=(0.159 x 0.0215 x 1050) / 2.70 × 10-3
=3.589/0.0027 = 1329.26
the Reynolds number for the blood leaving the heart through the aorta if the diameter of the aorta is 2.15 cm and the blood has a dynamic viscosity of 2.70 × 10-3 Pa·s, a density of 1050 kg/m3, and travels at a mean fluid velocity of 15.9 cm/s is 1329.26
which flow through the aorta in a Laminar flow
Note that
a) turbulen= Re >4000
b) laminar= Re <2300
c) transitioning between laminar and turbulen= Re between 2100 and 4000
