Given two points
and
The distance between them is >>>
![D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2}](https://tex.z-dn.net/?f=D%3D%5Csqrt%5B%5D%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D)
The points given are (Sqrt(20), Sqrt(50)) and (Sqrt(125), Sqrt(8)), so their distance is >>>
![\begin{gathered} D=\sqrt[]{(y_2-y_1)^2+(x_2-x_1)^2} \\ D=\sqrt[]{(\sqrt[]{8}-\sqrt[]{50})^2+(\sqrt[]{125}-\sqrt[]{20})^2} \\ D=\sqrt[]{(\sqrt8)^2-2(\sqrt[]{8})(\sqrt[]{50})+(\sqrt[]{50})^2^{}+(\sqrt[]{125})^2-2(\sqrt[]{125})(\sqrt[]{20})+(\sqrt[]{20})^2} \\ D=\sqrt[]{8-2(2\sqrt[]{2})(5\sqrt[]{2})+50+125-2(5\sqrt[]{5})(2\sqrt[]{5})+20} \\ D=\sqrt[]{8-40+50+125-100+20} \\ D=\sqrt[]{63} \\ D=3\sqrt[]{7} \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20D%3D%5Csqrt%5B%5D%7B%28y_2-y_1%29%5E2%2B%28x_2-x_1%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28%5Csqrt%5B%5D%7B8%7D-%5Csqrt%5B%5D%7B50%7D%29%5E2%2B%28%5Csqrt%5B%5D%7B125%7D-%5Csqrt%5B%5D%7B20%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B%28%5Csqrt8%29%5E2-2%28%5Csqrt%5B%5D%7B8%7D%29%28%5Csqrt%5B%5D%7B50%7D%29%2B%28%5Csqrt%5B%5D%7B50%7D%29%5E2%5E%7B%7D%2B%28%5Csqrt%5B%5D%7B125%7D%29%5E2-2%28%5Csqrt%5B%5D%7B125%7D%29%28%5Csqrt%5B%5D%7B20%7D%29%2B%28%5Csqrt%5B%5D%7B20%7D%29%5E2%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B8-2%282%5Csqrt%5B%5D%7B2%7D%29%285%5Csqrt%5B%5D%7B2%7D%29%2B50%2B125-2%285%5Csqrt%5B%5D%7B5%7D%29%282%5Csqrt%5B%5D%7B5%7D%29%2B20%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B8-40%2B50%2B125-100%2B20%7D%20%5C%5C%20D%3D%5Csqrt%5B%5D%7B63%7D%20%5C%5C%20D%3D3%5Csqrt%5B%5D%7B7%7D%20%5Cend%7Bgathered%7D)
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The midpoint formula is >>>
Plugging in the points, we have >>>
![\begin{gathered} M=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2}) \\ M=(\frac{\sqrt[]{20}+\sqrt[]{125}}{2},\frac{\sqrt[]{50}+\sqrt[]{8}}{2}) \\ M=(\frac{2\sqrt5+5\sqrt[]{5}}{2},\frac{5\sqrt[]{2}+2\sqrt[]{2}}{2}) \\ M=(\frac{7\sqrt[]{5}}{2},\frac{7\sqrt[]{2}}{2}) \end{gathered}](https://tex.z-dn.net/?f=%5Cbegin%7Bgathered%7D%20M%3D%28%5Cfrac%7Bx_1%2Bx_2%7D%7B2%7D%2C%5Cfrac%7By_1%2By_2%7D%7B2%7D%29%20%5C%5C%20M%3D%28%5Cfrac%7B%5Csqrt%5B%5D%7B20%7D%2B%5Csqrt%5B%5D%7B125%7D%7D%7B2%7D%2C%5Cfrac%7B%5Csqrt%5B%5D%7B50%7D%2B%5Csqrt%5B%5D%7B8%7D%7D%7B2%7D%29%20%5C%5C%20M%3D%28%5Cfrac%7B2%5Csqrt5%2B5%5Csqrt%5B%5D%7B5%7D%7D%7B2%7D%2C%5Cfrac%7B5%5Csqrt%5B%5D%7B2%7D%2B2%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29%20%5C%5C%20M%3D%28%5Cfrac%7B7%5Csqrt%5B%5D%7B5%7D%7D%7B2%7D%2C%5Cfrac%7B7%5Csqrt%5B%5D%7B2%7D%7D%7B2%7D%29%20%5Cend%7Bgathered%7D)
Answer:
This problem is unsolvable
Answer:
y=60° b=60°
Step-by-step explanation:
the sum of all degrees of interior triangle is 180
in the first one, 30° and 90° have been given.(that small square represent 90°)
so 180°-90°-30°=60°
in the second one, the 120° is on the other side of a line, a line has a degree of 180, therefore the interior angle is 60°, the same rule 180°-2*60°=60°
Answer:
Slope is 3/8
Step-by-step explanation:
( -1 + 4)/ (5 + 3)
3/ 8
Answer:
$27,014.85
Step-by-step explanation:
We're gonna use the compound interest formula: P = A(1 + r/n)^nt
P = final amount
A = starting amount (10,000)
r = rate (0.05)
n = times applied (4 since it's quarterly)
t = years (20)
P = 10,000(1 + 0.05/4)^4*20
P = 10,000(1.0125)^80
P = 27,014.84940753337
Round it to just 27,014.85
