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Diano4ka-milaya [45]
4 years ago
10

Factors of 3a^2+13a-10

Mathematics
1 answer:
Sholpan [36]4 years ago
7 0
Hi there!

3a² + 13a - 10
(3a - 2)(a+5)

----------------------------------------------------------------

I hope that helps!
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For f(x) = 4 - x and g(x) = 2x + x + 7, find the following functions.
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Answer: a. -3(x+1), b. 19-3x, c. -9 and d. 13

Step-by-step explanation:

Lets begin with a.  (fog)(x)=f(g(x))

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                                               substitute x by 3x+7)

                                             =4-(3x+7) =4-3x-7=-3x-3= -3(x+1).

                            b. (gof)(x)=g(f(x))=g(4-x) (where there is x in the function  

                                                g(x) we substitute with 4-x)

                                             = 3(4-x)+7 = 19-3x

                          c.  (fog)(2) = -3(2+1) = -9 (we now substitute x with 2 in -3(x+1). )

                           d. (gof)(2) = 19-3(2)=19-6=13. (Again we now substitute x with

                                               2 in 19-3x)

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