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eimsori [14]
3 years ago
14

First 4 terms 6,11,16,21 expression for the nth term

Mathematics
2 answers:
Inessa [10]3 years ago
6 0

Answer:

Tn=5n+1

Step-by-step explanation:

T9=5*9+1

T9=45+1

T9=50

Stolb23 [73]3 years ago
3 0

Answer:

5n + 1

Step-by-step explanation:

Increase by 5.

Variable term is 5n.

Number term is +1

5n + 1 :)

Hope this helps!

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If the total for this month's credit purchases is $550 at 24% annual interest, what is the total balance for the month after one
umka2103 [35]

Answer:

The total balance for the month after one month of interest accrues is $561 .

Step-by-step explanation:

Given as :

The principal credit in account = p = $550

The rate of interest = 24% annual

The time period = 1 month = \dfrac{1}{12} year

Let The Amount after one month of interest = $A

<u>Now, From Simple Interest method</u>

Simple Interest = \dfrac{\textrm principal \times \textrm rate\times \textrm time}{100}

Or, s.i = \dfrac{\textrm p \times \textrm r\times \textrm t}{100}

Or, s.i = \dfrac{550\times 24\times \frac{1}{12}}{100}

Or, s.i = \dfrac{13200}{1200}

Or, s.i = 11

∵ Amount = Principal + interest

So, A = s.i + p

Or, A = $11 + $550

∴  A = $561

So, The amount after one month on interest = A = $561

Hence, The total balance for the month after one month of interest accrues = A = $561 . Answer

4 0
4 years ago
The school production of​ 'Our Town' was a big success. For opening​ night, 315 tickets were sold. Students paid ​$1.50 ​each, w
LuckyWell [14K]

Answer:

There are 208 student and 107 non-student

Step-by-step explanation:

* Lets change the story problem to equations and solve them

- In the opening night 315 ticket were sold

- Each student paid $1.50 for a ticket

- Non-student paid $3.50 for a ticket

- The total money collected this night was $686.50

- Lets consider the number of student's ticket is x and the number

 of non-student's ticket is y

∵ The total number of the tickets is 315 tickets

∴ x + y = 315 ⇒ (1)

∵ The total amount of money is $686.50

∵ The cost of the student's ticket is $1.50

∵ The cost of the non-student's ticket is $3.50

∴ 1.50x + 3.50y = 686.50 ⇒ (2)

* Lets solve the two equation to find x and y by substitution method

- From equation (1) find x in term of y

∵ x + y = 315 ⇒ subtract y from both sides

∴ x = 315 - y ⇒ (3)

- Substitute x in equation (2) by equation (3)

∴ 1.50(315 - y) + 3.50y = 686.50 ⇒ open the bracket

∴ 472.50 - 1.50y + 3.50y = 686.50 ⇒ add the like terms

∴ 472.50 + 2y = 686.50 ⇒ subtract 472.50 from both sides

∴ 2y = 214 ⇒ divide both sides by 2

∴ y = 107

- Substitute the value of y in equation (1)

∴ x + 107 = 315 ⇒ subtract both sides by 107

∴ x = 208

∵ x represents the number of student's tickets and y represents

  the number of non-student's ticket

∴ There are 208 student and 107 non-student

6 0
4 years ago
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marishachu [46]
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Gemiola [76]

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Step-by-step explanation:

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3 years ago
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