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ira [324]
4 years ago
6

Examine the graph at right. Then, in a sentence or two, suggest reasons why the graph rises at 11:00am and then drops at 1:15pm.

Mathematics
2 answers:
VLD [36.1K]4 years ago
5 0

Answer:

This is a graph of Time vs. Amount in the dollar ( $) in Lacy's purse.

This graph shows the total Amount Lacy has in her purse from 6:00 a.m. to 6:00 p.m.

She had nearly $ 70 from 6:00 a.m. to 11:00 a.m.

then nearly $ 140 from 11:00 a.m. to 1:15 p.m.

then nearly $ 100 from 1:15 p.m. to 6:00 p.m.

So, we see a rise and fall in amount kept in Lacy's purse.

There may be many reasons behind it. One of the reasons can be that "At 11:00 a.m. she is going outside the house so, she kept money in the purse. So, there is a rise in the graph then at 1:15 p.m. she had bought something. So, there is a drop at 1:15 p.m. "

ArbitrLikvidat [17]4 years ago
3 0
Based on the graph shown above, the graph rises at about 11:00 AM and drops again at 1:15 PM. The graph is Lacy's purse vs time, this means that the values involve money and time. The only reason that would explain the drop in value at 1:15 PM is that Lacy went to lunch and spent money. 
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Answer:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

\mu = 34 represent the mean

\sigma= 5 represent the deviation

We have a sample size of n = 54 and we want to find this probability:

P(33.3 < \bar X< 34.3)

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

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