Answer:
4 Soccer balls and 6 Basketballs
Step-by-step explanation:
You can solve this problem by setting up a system of equations. Letting x be Soccer balls and y be Basketballs. Remember, Money goes with, Money goes with Money, meaning that for this problem the first equation that can be made is $248 = $28y + $20x with Y being basketballs and x being soccerballs. Next is a little more difficult. You will be creating the equation y=3x-6 because it is 6 less than 3 times the amount of x or Soccer balls. From here you can plug in the equations into a graphing calculator and graph it and see where the two lines intersect. This would be at (4, 6). When I said to let x equal Soccer Balls and y equal basketballs that is where I got the 4 soccer balls and 6 basketballs.
Let x be equal to Jim's travel time
Let x + 2 be equal to Joan's travel time
distance = speed*travel time
6(x + 2) + 8x = 33
6x + 12 + 8x = 33
14x = 21
x = 21/14 = 3.5
3.5 hrs is the hours that Jim have been running until he met Joan.
Answer:
Step-by-step explanation:
Use the formula,
distance = √[(x1-x2)^2 + (y1-y2)^2]
-10-a/-4-(-2) = 8
-10-a / -2 = 8
-10 - a = -16
-a = -6
a=6
