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tia_tia [17]
3 years ago
13

find the value of the polygon. the polygon has 6 interior angles 2 of them are y and 4 of them are (2Y-20)

Mathematics
1 answer:
Anna35 [415]3 years ago
3 0
First we need to determine what the 6 angles must add to. Turns out we use this formula

S = 180(n-2)

where S is the sum of the angles (result of adding them all up) and n is the number of sides. In this case, n = 6. So let's plug that in to get

S = 180(n-2)
S = 180(6-2)
S = 180(4)
S = 720

The six angles, whatever they are individually, add to 720 degrees. The six angles are y, y, 2y-20, 2y-20,  2y-20,  2y-20, <span> 

They add up and must be equal to 720, so let's set up the equation to get...

(y)+(y)+(</span>2y-20)+(2y-20)+(2y-20)+(<span>2y-20) = 720

Let's solve for y

</span>y+y+2y-20+2y-20+2y-20+2y-20 = 720

10y-80 = 720

10y-80+80 = 720+80

<span>10y = 800
</span>
10y/10 = 800/10

y = 80

Now that we know the value of y, we can figure out the six angles

angle1 = y = 80 degrees
<span>angle2 = y = 80 degrees
</span><span>angle3 = 2y-20 = 2*80-20 = 140 degrees
</span>angle4 = 2y-20 = 2*80-20 =<span> 140 degrees
</span><span>angle5 = 2y-20 = 2*80-20 = 140 degrees
</span>angle6 = 2y-20 = 2*80-20 =<span> 140 degrees
</span>
and that's all there is to it
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Alexeev081 [22]

Answer:

Step-by-step explanation:

Let the 3 numbers be 4x , 5x and 6x

4x + 6x = 5x + 55

10x = 5x + 55                      Subtract 5x from both sides.

<u> 5x     5x</u>

5x = 55                                Divide by 5

x = 55/5

x = 11

Therefore the numbers are

3*11 = 33

4*11 = 44

5*11 = 55

8 0
3 years ago
Plz help! Determine whether the equation represents a direct variation. If it​ does, find the constant of variation.
Finger [1]

Answer:

It does not have a direct variation, because y doesnt vary directly with x

Step-by-step explanation:

Hope This Helps!!!

8 0
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Q2-b2Evaluate if a=4 and b =-2​
lesya692 [45]

Answer:

12

Step-by-step explanation:

Plug the given values into the equation to solve.

a² - b²

(4)² - (-2)²

16 - 4

12

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Draw a model to show a fraction that is equivalent to 1/3 and a fraction that is not equivalent to 1/3
klemol [59]
Steps:
1. Draw a long box
2. Draw a horizontal line down the center of the box
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3 years ago
Expand (2 + a)9 using Pascal’s triangle.
Natalija [7]

Answer:

Step-by-step explanation:

The Pascal triangle is used to determine the coefficients of the terms when we expand the expression.

                                             1                                (A + B) ^ 0 = 1

                                         1       1                            (A +B ) ^ 1 = 1A + 1B

                                   1          2        1          (A+ B) ^ 2 = 1A^2 + 2 AB + 1B^2

By extending the triangle, you will get the 9th row, which is your expression, of the coefficients. that is

1          9       36    84    126    126    84    36    9    1

Now, fill in AB in the gaps.

1AB + 9 AB + 36AB + 84AB + 126AB + 126AB +84AB + 36AB + 9AB + 1AB

Next, you need to go from the left to fill out the exponent of A and it will go down from 9 (the exponent of the whole thing) . That is

1A^9B+9A^8B+36A^7B+84A^6B+126A^5B+126A^4B+84A^3B+36A^2B+9A^1B+1A^0B

Next will be the exponent of B. this time, you go from the right and do the same with A. You can go from the left also, but go up from 0 to 9 for the exponent of B

1A^9B^0+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+1A^0B^9

The last step is just to simplify the A^0=1 and B^0 =1 at the first and the last terms.

A^9+9A^8B^1+36A^7B^2+84A^6B^3+126A^5B^4+126A^4B^5+84A^3B^6+36A^2B^7+9A^1B^8+B^9

Hope you can learn the method

5 0
3 years ago
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