Answer:
The correct answer would be Light independent reactions require the energy gathered in the thylakoids.
Photosynthesis can divided into two sub-processes or reactions:
Light-dependent reaction: It converts solar energy into chemical energy that is, ATP (adenosine triphosphate) and NADPH with the help of photolysisis of water. It takes place in thyllakoid membrane of the chloroplast.
Light-independent reaction: It fixes carbon obtained from carbon dioxide into the food or glucose with the help of enzyme RuBisCO (Ribulose-1,5-bisphosphate carboxylase/oxygenase).
It takes place in the stroma of the chloroplast and does not require the involvement of light however, it requires the products (ATP and NADPH) of the light reaction.
Fixation of 1 molecule of glucose requires 6 molecules of carbon dioxide, 9 molecules of ATP and 6 molecules of NADPH.
So, darkness indirectly affects the light-independent reaction.
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By examining large sample sizes, Mendel showed that his crosses behaved reproducibly according to the laws of probability, and that the traits were inherited as independent events. Two rules in probability can be used to find the expected proportions of offspring of different traits from different crosses.
To find the probability of two or more independent events occurring together, apply the product rule and multiply the probabilities of the individual events. The use of the word “and” suggests the appropriate application of the product rule. To find the probability of two or more events occurring in combination, apply the sum rule and add their individual probabilities together. The use of the word “or” suggests the appropriate application of the sum rule.
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Answer:
a. purple allele (C) = 0.609, pink allele (c) = 0.391
b. purple homozygotes = 371, pink homozygotes = 153, heterozygotes = 476
Explanation:
Given -
Purple flowers - 847
Pink flowers - 153
The frequency of recessive genotype i.e
Frequency of recessive allele i.e q is equal to
As per hardy Weinberg's first equilibrium equation -
Frequency of purple homozygous species
Number of purple homozygous species 
Number of pink homozygous species 
Heterozygous species is equal to
<span>let the pair of glasses in each layer in small box= x
and the pair glasses in each layer in large box= x-2
total pair of glasses in large box= 5(x-2)
total pair of glasses in small box= 1x</span>
