Question

Qb−→− bisects ∠pqr and m∠bqr=15.4∘. Find m∠pqb and m∠pqr.

Answer 1

SOLUTION-

Here

$m \angle BQR = 15.4^{\circ}$

As QB is the angle bisector so,

$m \angle PQB = m \angle BQR$

∴ $m \angle PQB= 15.4^{\circ}$

As,

$m \angle PQR = m \angle PQB+m \angle BQR =15.4^{\circ}+15.4^{\circ} = 30.8^{\circ}$

∴  $m \angle PQR= 30.8^{\circ}$

Answer 2

Answer:

i) ∠PQB = 15.4°

ii) ∠PQR = 30.8°

Step-by-step explanation:

The line segment QB bisects ∠PQR.

If QB bisects ∠PQR means the line segment divides the ∠PQR into two equal angles.

So, ∠PQB = ∠BQR

Given ∠BQR = 15.4°

So, ∠PQB = 15.4°

∠PQR = ∠PQB + ∠BQR

∠PQR = 15.4° + 15.4°

∠PQR = 30.8°