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jok3333 [9.3K]
3 years ago
15

Taylor graphs the system below on her graphing calculator and decides that f(x)=g(x) at x=0, x=1, and x=3. Provide Taylor some f

eedback that explains which part of her answer is incorrect and why it is incorrect. f(x)=2x+1
g(x)=2x^2+1

Mathematics
1 answer:
goblinko [34]3 years ago
5 0

Answer:

f(x)=g(x) at x= 0 and x= 1 and not at x= 3.

Step-by-step explanation:

We have the functions, f(x)=2x+1 and g(x)=2x^2+1.

It is given that,

At x=0, x=1, and x=3, f(x)=g(x)

i.e. 2x+1=2x^2+1

i.e. 2x^2-2x=0

i.e. 2x(x-1)=0

i.e. x= 0 and (x-1)= 0

i.e. x= 0 and x= 1.

Also, after plotting the graphs of both the functions, we see their intersection point are (0,1) and (1,3).

Thus, we get that f(x)=g(x) at x= 0 and x= 1 and not at x= 3.

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Subtract the equations, you get:

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x + 15/7 = 6
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x = (42-15)/7
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Shalnov [3]

|x - 3| - 1 = 5

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x = - 3

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