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Snezhnost [94]
3 years ago
7

The perimeters of two similar figures are 15 in. and 24 in. What is the ratio of the areas of the two figures? State your answer

as a fraction.
Mathematics
1 answer:
kkurt [141]3 years ago
5 0

Answer:

25/64

Step-by-step explanation:

ratio of perimeters = 15/24 = 5/8

ratio of areas = square of ratio of perimeters

ratio of areas = (5/8)^2 = 25/64

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Solve for x, given the equation Square root of x-5+7=11
denis-greek [22]

\sqrt{x-5+7} = 11\\x-5+7 = 11^2\\x-5+7 = 121\\x + 2 = 121\\x = 119

Check the answer:

\sqrt{119-5+7} \\\sqrt{114+7} \\\sqrt{121} \\11

This answer is correct,

x = 119

6 0
3 years ago
A circle with radius of 5 cm sits inside a 11 cm * 11 cm rectangle.
Nadusha1986 [10]

Answer:

42.43  cm^{2}

Step-by-step explanation:

Given:

A circle with a radius of 5 cm sits inside a 11 cm x 11 cm rectangle.

Question asked:

What is the area of the shaded region as shown in the figure ?

Solution:

First of all calculate area of circle and then area of rectangle:-

Area\ of\  cirle=\pi r^{2}

                      =\frac{22}{7} \times5\times5\\ \\ =\frac{550}{7}\\  \\=78.571\   cm^{2}\\

<u>As here length an width both are 11 cm, we can say that this is a square.</u>

<u />Area\ of\ square=(Side)^{2}

                         =11\times11=121\ cm^{2}

Now, area of shaded region = Area of square - Area of circle

                                               = 121 - 78.571 = 42.429 cm^{2}

Therefore, the area of the shaded region will be 42.43  cm^{2}

Download docx
5 0
3 years ago
Tom needs to drive 21 miles to work. So far, he has driven 2.2 miles. How many more miles must he drive?
wolverine [178]
Tom needs to drive 18.8 more miles
4 0
3 years ago
Read 2 more answers
A bag of potatoes weighs about
ruslelena [56]
Bag of potatoes are usually 10 pounds
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2 years ago
A cash box contains $74 made up of quarters, half-dollars, and one-dollar
Strike441 [17]

Answer:

25 one-dollar coins, 16 half-dollar coins, and 164 quarters

Step-by-step explanation:

First, set up equations based on the information given:

0.25q+0.50h+1.00d=74

\displaystyle{h=\frac{3}{5}d+1}

q=4(d+h)

Then, substitute <em>q</em> in the first equation with the expression from the third equation:

0.25[4(d+h)]+0.50h+1.00d=74\\1d+1h+0.50h+1.00d=74\\2d+1.5h=74

Next, substitute <em>h</em> in that equation with the expression from the second equation:

\displaystyle{2d+1.5(\frac{3}{5}d+1)=74}

2d+0.9d+1.5=74\\2.9d+1.5=74

Solve for <em>d</em>, the number of one-dollar coins:

2.9d+1.5=74\\2.9d=72.5\\d=25

Substitute 25 for <em>d</em> in the second equation to find <em>h</em>, the number of half-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{h=\frac{3}{5}(25)+1}

h=15+1\\h=16

Substitute 25 for <em>d</em> and 16 for <em>h</em> in the third equation to find <em>q</em>, the number of quarters:

q=4(d+h)\\q=4(25+16)\\q=4(41)\\q=164

Then, verify that the coins total $74:

0.25(164)+0.50(16)+1.00(25)=74\\41+8+25=74\\74=74\\\text{Check.}

Next, verify that the number of half-dollar coins is one more than three-fifths of the number of one-dollar coins:

\displaystyle{h=\frac{3}{5}d+1}

\displaystyle{16=\frac{3}{5}(25)+1}

16 = 15 + 1\\16 = 16\\\text{Check.}

Finally, verify that the number of quarters is four times the number one-dollar and half-dollar coins together:

q=4(d+h)\\164=4(25+16)\\164=4(41)\\164=164\\\text{Check.}

6 0
3 years ago
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