Answer:
This does not mean that he would complete exactly 65 passes.
The probability that he completes exactly 65 passes is only 8.34%
65% is the number of passes he would be expected to complete in a very large sample(like 13 NFL seasons, not just a single season).
Step-by-step explanation:
There is not a 100% probability that he completes exactly 65 passes. So, it does not mean that he would complete exactly 65 passes.
How I arrived at this answer?
For each pass that he throws, either it is complete, or it is not. Since there are only two outcomes, we have a binomial probability distribution.
Binomial probability distribution
The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

In which
is the number of different combinatios of x objects from a set of n elements, given by the following formula.

And
is the probability of X happening.
In this problem, we have that:
There are 100 passes, so 
Each pass a 65% probability of being completed, so 
So

