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4 years ago

45 + 5 = what i need so HELP

Mathematics

2 answers:

anzhelika [568]4 years ago

7 0

your answer will be 50 because if you add 45 plus 5 more give u 50

andreyandreev [35.5K]4 years ago

6 0

50 is the answer hope i helped!

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I get HOW to make a box and whisker plot. What I don't get is WHY you would want to make one. From a practical point of view, wh

ratelena [41]

Answer:

I'd say go to Wikipedia and look it up. It is something that cannot be summarized into just a few words.

Step-by-step explanation:

4 0

3 years ago

Solve for x 1+4x=-5+7x

SVETLANKA909090 [29]

Steps to solve:

1 + 4x = -5 + 7x

~Subtract 1 to both sides

4x = -6 + 7x

~Subtract 7x to both sides

-3x = -6

~Divide -3 to both sides

x = 2

Best of Luck!

6 0

3 years ago

Read 2 more answers

WILL MARK BRAINLIEST Olivier has $48.25 to spend on painting classes. Each class costs $6 plus a one-time registration fee of $6

Nutka1998 [239]

Answer:

A. 6n+6.25 = 48.25

Step-by-step explanation:

$48.25 Money to spend

Each class costs $6 plus

one time $6.25

N= # of classes

6= slope rise over run

48.25 is total

6.25 is the y-intercept First time payment

u only pay once

48.25=6n+6.25

8 0

3 years ago

Mark true or false to indicate whether the ratios are equivalent or not

Ann [662]

Answer:

1) False

2) True

3) True

4) False

Step-by-step explanation:

Divide second numerator by the first numerator

Do this to the denominators as well

Compare the numbers and if they are the same then they are equal to eachother

8 0

3 years ago

Read 2 more answers

X² - 6x + 4 = 0<br><br> solve and show work. ...?

ycow [4]

The answer is 3 + √5 and 3 - √5.

This is quadratic equation: x² - 6x + 4 = 0
The general quadratic equation is ax² + bx + c = 0
Our equation can be rewritten: 1x² + (-6)x + 4 = 0
So, in our equation we have: a = 1, b = -6, c = 4

Now, x can be calculated using the formula: $x_{1,2}= \frac{-b+/- \sqrt{ b^{2}-4ac } }{2a}$
$x_{1,2} =\frac{-(-6)+/- \sqrt{ (-6)^{2}-4*1*4 } }{2*1} = \frac{6+/- \sqrt{36-16} }{2} = \frac{6+/- \sqrt{20} }{2} =\frac{6+/- \sqrt{4*5} }{2}= \\ 
=\frac{6+/- \sqrt{4}* \sqrt{5} }{2} =\frac{2*3+/- 2\sqrt{5} }{2}= \frac{2(3+/- \sqrt{5}) }{2} =3+/- \sqrt{5}$

From here:
$x_{1} =3+ \sqrt{5} \\ 
x_{2} =3- \sqrt{5}$

6 0

4 years ago