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wolverine [178]
3 years ago
14

Willow Creek Nursery, with an authorization of 72,000 shares of preferred stock and 210,000 shares of common stock, completed se

veral transactions involving its stock on October 1, the first day of operations. The trial balance at the close of the day follows Willow Creek Nursery
UNADJUSTED TRIAL BALANCE

October 1, 20--

ACCOUNT TITLE

DEBIT

CREDIT

1

Cash

4,000,500.00

2

Land

860,000.00

3

Buildings

2,533,000.00

4

Common Stock

2,540,000.00

5

Paid-In Capital in Excess of Par-Common Stock

1,460,500.00

6

Preferred Stock

2,925,000.00

7

Paid-In Capital in Excess of Par-Preferred Stock

468,000.00

8

Totals

7,393,500.00

7,393,500.00

Common stock has a $20 par value and the preferred stock is 1%, 75 par value. All shares within each class of stock were sold at the same price. The preferred stock was issued in exchange for the land and buildings.

Journalize the two entries to record the transactions summarized in the trial balance.
Business
1 answer:
Katyanochek1 [597]3 years ago
4 0

Answer:

Explanation:

The journal entries are shown below:

1. Cash A/c Dr $4,000,500

         To Common stock $2,540,000

         To Paid-In Capital in Excess of Par-Common Stock  $1,460,500

(Being issuance of the common stock is recorded)

2. Land A/c Dr $860,000

   Building A/c Dr $2,533,000

        To Preferred Stock  $2,925,000

        To Paid-In Capital in Excess of Par-Preferred Stock  $468,000

(Being issuance of the preferred stock is recorded)

All other information which is given is not relevant. Hence, ignored it

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Horses cost $10, pigs cost $3, and rabbits are only $0.50. A farmer buys 100 animals for $100, How many of each animal did he bu
VMariaS [17]

Answer:

The correct answer to the following question is that there are 5 horses, 1 pig and 94 rabbits.

Explanation:

Given information -

Horses cost = $10

Pigs = $3

Rabbits = $.50

There are total of 100 animals, which are bought for $100 in total.

So by using simple equations we can solve this problem,

where let number of horses be x

number of pigs be y

number of rabbits be z

so the first equation that we can make by using given information is -

x + y + z = 100 (total of 100 animals bought )  _ _ equation 1

10 x + 3 y + .5 z = $100 _ _ equation 2

Now multiplying equation 2 by 2 and then subtract that from equation 1

(10 x + 3 y + .5 z = $100) x 2

= 20 x + 6 y + z = $200  _ _ equation 3

Now subtracting equation 3 from 1 -

20 x + 6 y + z = $200

          -

x + y + z = 100

19 x + 5 y = 100

Here 19 x and 5 y have to be a multiple of 5 ( where x and y are integers ), therefore the only possible value of x here can be 5 and if the value of x =5 , then the value of y will be equal to 1,

19 x 5 + 5 x 1 = 100

Now putting the value of x and y in equation 2,

10 x 5 + 3 x 1 + .5 x z = $100

50 + 3 + .5 z = 100

.5 z = 47 ( 100 - 53 )

z = 47 / .5

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The correct answer should be D
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Answer & Explanation:

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2) Borrowings       Cash (+7...)                                            Loan (+7...)

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4) Revenue          Cash (+298...)                Income (+298...)  

5) Expense           Cash (-210...)                 Expense (-210...)

3)* Price paid = 8700 or 8600 , Final price = 8300 or 7940 , Gain (Discount received) = 8700 - 8300 ie 400 (or) 8600 - 7940 = 660

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