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AVprozaik [17]
3 years ago
7

A box contains 3 plain pencils and 7 pens. A second box contains 9 color pencils and 3 crayons. One item from each box is chosen

at random. What is the probability that a pen from the first box and a crayon from the second box are selected? Write your answer as a fraction in simplest form.
Mathematics
1 answer:
Anastasy [175]3 years ago
3 0
P(P then C)=(7/10)(3/12)

P(PthenC)=21/120

P(PthenC)=7/40
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Two ships leave the same port in different directions, forming a 120° angle between them. One ship travels 70 mi. and the other
kondaur [170]

Answer : Distance between the ships to the nearest miles = 106.03 ≈ 106 mi.

Explanation :

Since we have shown in the figure below :

a=70 mi.

b=52 mi.

c=x mi.

\text{Since two ships leaves the same port in different directions forming a }120\textdegree\text{angle between them.}

So, we use the cosine rule , which states that

 c^2=a^2+b^2-2ab.cosC\\\\x^2=70^2+52^2-2\times 70\times 52\times cos(120\textdegree)\\\\x^2=4900+2704-7280\times (-0.5)\\\\x^2=7604+3640\\\\x^2=11244\\\\x=\sqrt{11244}\\\\x=106.03

So, c = x= 106.03 mi.

Hence, distance between the ships to the nearest miles = 106.03 ≈ 106 mi.


8 0
3 years ago
Cx=r/d<img src="https://tex.z-dn.net/?f=%5Cfrac%7Br%7D%7Bd%7D" id="TexFormula1" title="\frac{r}{d}" alt="\frac{r}{d}" align="abs
antoniya [11.8K]

Answer:

x=\frac{rc}{d}

Step-by-step explanation:

ill take the equation as this

cx=\frac{r}{d}

divide both side by c

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{\frac{b}{c}}=\frac{a\cdot \:c}{b}

Next time when you see someone greif your question, please report it.

Shame for the other guy

Hoped this helped you

Red

8 0
3 years ago
3x+11 divided by 2+-2
mezya [45]

Answer:

Impossible.

Step-by-step explanation:

You cannot divide by a 0.

6 0
3 years ago
Read 2 more answers
URGENT please help!!! I need a explanation please!! You own a restaurant and can reopen as long as people seated at a table are
hram777 [196]

Answer:

1) Maximum number of tables that can be kept in the dinning room is 10 tables

2)The maximum number of customers, given 6 people per table is 60 customers

Step-by-step explanation:

The parameters given are;

Distance between people seated at different tables = 6 ft

Dimension of table = 2 m by 1.5 m

Number of people at a table = 6 people

Dimension of dinning;

Width = 12 m

Length = 20 m

Dimension of entrance;

Width = 20/21*30  m

Length = 10 m

With 6 meters between tables and a table with of 1.5, we have for the arrangement in the question;

3 tables = 4.5 m

Distance between = 2 × 6 = 12

4.5 + 12 = 16 m (More room required)

With two tables, we have;

Width of tables = 2×1.5 = 3 m

Distance between = 6 m

Dining room width required = 3 + 6 = 9 m

Therefore, the maximum tables in each row = 2

Given that the dining room area extends to the entrance area, total length = 30 m.

With 4 tables we have;

Length = 4 × 2 + 6 × 3 = 26

While on the entrance side of the dinning room area which is 20 m, we have 3 tables;

Length = 3 × 2 + 6 × 2 = 18

Therefore, both arrangements are acceptable;

Just on entering by the right the length = 20/21×30 m

Therefore, with 3 tables will required number due to proximity wit the door and tables arranged along the right wall of the dinning

1) Maximum number of tables that can be kept in the dinning room = 4 + 3 + 3 = 10 tables

2)The maximum number of customers, given 6 people per table = 6×10 = 60 customers.

4 0
3 years ago
Which two of the following numbers have the same value?
Oksi-84 [34.3K]

Answer:

33 and 42

Step-by-step explanation:

7 0
3 years ago
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