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3 years ago

Write the statement in the if then form perpendicular lines intersect to form right angles

Mathematics

1 answer:

kvv77 [185]3 years ago

8 0

Answer: If perpendicular lines intersect, then they form right angles.

Step-by-step explanation:

You take the first part, "perpendicular lines intersect", and add the "if" to it. Then, you take the second part, "to form right angles", and add the "then" in front of it to get your answer, "If perpendicular lines intersect, then they form right angles."

Hope it helps! :)

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600+15y=750.<br> solve for y<br> can I as well have the way you solved for y?

Pie

1.)subtract 600 from 750 in order to simplify
2.)divide by 15 on both sides to get y alone. Doing this cancels the 15 on the y and makes the right side equal 10
3.)y=10

4 0

3 years ago

Read 2 more answers

Step 3: 2x > 10 Step 4: x > 5 What property justifies the work between step 3 and step 4? A. division property of inequali

BigorU [14]

Answer:

A. Division property of inequality.

Step-by-step explanation:

Let be $2\cdot x > 10$ , we proceed to show the appropriate procedure to step 4:

1) $2\cdot x >10$ Given

2) $x > 5$ Compatibility with multiplication/Existence of multiplicative inverse/Associative property/Modulative property/Result. (Division property of inequality)

In consequence, the division property of inequality which states that:

$\forall\, a, b, c \in \mathbb{R}$ . If $c > 0$ , then:

$a> b\,\longrightarrow a\cdot c > b\cdot c \,\lor\, a$

But if $c < 0$ , then:

$a> b\,\longrightarrow a\cdot c < b\cdot c \,\lor\, a b\cdot c$

Hence, correct answer is A.

5 0

3 years ago

Carlos earns $3.50 a day on his paper route. He runs

loris [4]

Answer:

their are 4 weeks in a month so 4*7=

so its 1/28 which is equals to (1 divided by 28)

3.57%

Hope This Helps!!!

6 0

2 years ago

Read 2 more answers

The London theater offers child tickets at 10$each and adult tickets at 20$ each.Mrs burham buys 34 tickets at a total cost of 5

kirill115 [55]

Answer:

A+C=34

10C+20A=570

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3 years ago

Which equation is parallel to the line LaTeX: y=\frac{1}{2}x+3y = 1 2 x + 3and passes through the point (10, -5)?

sukhopar [10]

Answer:

$Equation\ of\ line:\ y=\frac{1}{2}x-10$

Step-by-step explanation:

$Let\ the\ required\ equation\ is\ y=mx+c\\\\where\ m\ is\ the\ slope\ of\ the\ equation\ and\ c\ is\ y-intercept\\\\It\ is\ parallel\ to\ the\ equation\ y=\frac{1}{2}x+3\\\\Hence\ slope\ of\ these\ two\ lines\ will\ be\ same.\\\\Slope\ of\ y=\frac{1}{2}x+3\ is\ \frac{1}{2}\\\\Hence\ slope\ of\ y=mx+c\ is\ \frac{1}{2}\Rightarrow m=\frac{1}{2}\\\\Equation:y=\frac{1}{2}x+c\\\\Line\ passes\ through\ (10,-5).\ Hence\ this\ point\ satisfies\ the\ equation\ of\ line.\\\\-5=\frac{1}{2}\times 10+c$

$-5=-5+c\\\\c=-10$

$Equation\ of\ line:\ y=\frac{1}{2}x-10$

8 0

3 years ago