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4 years ago

Find the quotient of `(2i(4+5i)(4-5i))/(4+i)`, and express it in the simplest form.

Mathematics

1 answer:

DIA [1.3K]4 years ago

5 0

Answer:

(328i + 82) / 17

Step-by-step explanation:

`(2i(4+5i)(4-5i))/(4+i)

= (2i(16 - 25i^2)) / (4 + i)

= (2i( 16 + 25) )) / (4 + 1) [Note:- i^2 = -1]

= 82i / (4 + i)

= 82i(4 - i) / (4 + i)(4 - 1)

= 328i + 82 / (16 - i^2)

= (328i + 82) / 17

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Find the unit rate: 5 bags of Hot Cheetos cost $4.32.

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3 years ago

To maintain an acceptable level of chlorine in your pool you add 1.4gallins of chlorine.This is 0.007℅ of the amount of water in

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3 years ago

Which angle pairs are supplementary? Check all that<br> apply.

Basile [38]

Answer:

The correct answers are B, C, and E.

B. < 4 and < 3

C. < 4 and < 5

E. < 3 and < 6

Step-by-step explanation:

The pairs in options B, C, and E add up to 180°, which is the definition of a supplementary angle.

Hope this helps!

8 0

3 years ago

A box contains four red balls and eight black balls. Two balls are randomly chosen from the box, and are not

castortr0y [4]

P(B) = 8/12

P(R | B) = 4/11

P(B ∩ R) = 8/33

The probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

<em><u>Solution:</u></em>

<em><u>The probability is given as:</u></em>

$Probability = \frac{\text{number of favorable outcomes}}{\text{total number of possible outcomes}}$

Given that,

A box contains four red balls and eight black balls

Red = 4

Black = 8

Total number of possible outcomes = 12

Let event B be choosing a black ball first and event R be choosing a red ball second.

$P(B) = \frac{8}{12}$

$P(B n R) = P(B) \times P(R)\\\\P(B n R) = \frac{8}{12} \times \frac{4}{11}\\\\P(B n R) = \frac{8}{33}$

<h3><u>Find </u><u> P(R | B)</u></h3><h3> $P(R | B) = \frac{P(R n B)}{P(B)}\\\\P(R | B) = \frac{\frac{8}{33}}{\frac{8}{12}}\\\\P(R | B) = \frac{8}{33} \times \frac{12}{8}\\\\P(R | B) = \frac{4}{11}$ </h3>

<em><u>The probability that the first ball chosen is black and the second ball chosen is red is about percent</u></em>

$\frac{8}{33} \times 100 = 0.24 \times 100 = 24 \%$

Thus the probability that the first ball chosen is black and the second ball chosen is red is about 24% percent

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Ivenika [448]

Answer:

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Step-by-step explanation:

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