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erica [24]
3 years ago
13

a culinary student decorates a 8-in. -diameter round cake. What is the approximate are of the top of the cake?

Mathematics
2 answers:
Rom4ik [11]3 years ago
8 0

Answer:

The top of the cake is 25.12 in²

Step-by-step explanation:

Hello!

So you are dealing with a circumference question! And because the diameter is 2x the radius, we know the radius is actually 4.

Lets write out the circumference formula and use that to help us.

c = 2\\\pi x r

pi is 3.14....

But lets use 3.14

c = 2(3.14) x 4

Plus this into a calculator and we get 25.12 as the answer.

Elena-2011 [213]3 years ago
3 0

Answer:

≈50.265 in^{2}

Step-by-step explanation:

You first have to find the radius since the formula for the area of a circle is  A=\pi r^{2}.

Since the radius is half the diameter, just divide 8 by 2 which will give you 4.

r=4

Now plug in the radius into the formula and simplify.

A=\pi 4^{2}

A=\pi 16

≈50.265 in^{2}

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LAST ONE GUYSSS \small \angle L and \small \angle M are supplementary, \small m\angle L=12x+45 and \small m\angle M=18x-30. Dete
svp [43]

Answer:

m\angle L = 111\degree \\m\angle M = 69\degree

Step-by-step explanation:

Since, angle L and angle M are supplementary.

\therefore m\angle L + m\angle M= 180\degree  \\ \therefore \: 12x + 45 + 18x - 30 = 180 \degree \\ \therefore \: 30x + 15= 180 \degree\\ \therefore \: 30x= 180 \degree - 15 \degree\\ \therefore \: 30x= 165 \degree  \\ x =  \frac{165 \degree}{30}  \\ x = 5.5 \degree \\  \\ m\angle L  = 12x + 45  \\ m\angle L = 12 \times 5.5 + 45 \\ m\angle L  = 66 + 45 \\ \huge \red{ \boxed{ m\angle L  = 111 \degree}} \\  \\ m\angle M=18x - 30 \\ m\angle M=18 \times 5.5 - 30 \\ m\angle M=99 - 30 \\ \huge \purple{ \boxed{ m\angle M=69 \degree}} \\

6 0
3 years ago
The heights of 40 randomly chosen men are measured and found to follow a normal distribution. An average height of 175 cm is obt
AVprozaik [17]

Answer:

95% two-sided confidence interval for the true mean heights of men is [168.8 cm , 181.2 cm].

Step-by-step explanation:

We are given that the heights of 40 randomly chosen men are measured and found to follow a normal distribution.

An average height of 175 cm is obtained. The standard deviation of men's heights is 20 cm.

Firstly, the pivotal quantity for 95% confidence interval for the true mean is given by;

                             P.Q. = \frac{\bar X-\mu}{\frac{\sigma}{\sqrt{n} } }  ~ N(0,1)

where, \bar X = sample average height = 175 cm

            \sigma = population standard deviation = 20 cm

            n = sample of men = 40

<em>Here for constructing 95% confidence interval we have used One-sample z test statistics as we know about population standard deviation.</em>

So, 95% confidence interval for the true mean, \mu is ;

P(-1.96 < N(0,1) < 1.96) = 0.95  {As the critical value of z at 2.5%

                                     level of significance are -1.96 & 1.96}  

P(-1.96 < \frac{\bar X-\mu}{\frac{s}{\sqrt{n} } } < 1.96) = 0.95

P( -1.96 \times }{\frac{\sigma}{\sqrt{n} } } < {\bar X-\mu} < 1.96 \times }{\frac{\sigma}{\sqrt{n} } } ) = 0.95

P( \bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } } < \mu < \bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } } ) = 0.95

<u>95% confidence interval for </u>\mu = [ \bar X-1.96 \times }{\frac{\sigma}{\sqrt{n} } } , \bar X+1.96 \times }{\frac{\sigma}{\sqrt{n} } } ]

                                            = [ 175-1.96 \times }{\frac{20}{\sqrt{40} } } , 175+1.96 \times }{\frac{20}{\sqrt{40} } } ]

                                            = [168.8 cm , 181.2 cm]

Therefore, 95% confidence interval for the true mean height of men is [168.8 cm , 181.2 cm].

<em>The interpretation of the above interval is that we are 95% confident that the true mean height of men will be between 168.8 cm and 181.2 cm.</em>

3 0
3 years ago
HELP ASAP PLEASE!!!!!
xeze [42]

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The orginial price of a pumkin is 3 $ if there is a sale of 25 percent of what is the orginial price
GarryVolchara [31]

Answer:

$12

Step-by-step explanation:

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2 years ago
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Answer:

\frac{9}{5} \\ \\ OR\\ \\ 1\frac{4}{5}

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3 0
3 years ago
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