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3 years ago

the parking lot has five rows there are 10 parking spaces in the truck how many parking spaces are in the lot

Mathematics

1 answer:

Anika [276]3 years ago

4 0

There are 50 parking spaces because 10×5=50

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The South Memorial School is designing a new playground. There will be a walkway that diagonally crosses the square playground.

cestrela7 [59]

The playground is a square, so there will be a right triangle formed by diagonal and two sides. So sides length²*2=diagonal length². So the side length is 38.9 meter.

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2 years ago

A man drove 210 miles in 3.5 hours. If the posted speed limit was 55 mph (miles per hour) the entire way, approximately how many

Alona [7]

Answer:

5mph over the speed limit

Step-by-step explanation:

In 1 hour the man drove 210/3.5=60 miles. 60mph is over the speed limit (55) by 5 mph.

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2 years ago

The probability distribution of the amount of memory X (GB) in a purchased flash drive is given below. x 1 2 4 8 16 p(x) .05 .10

Rama09 [41]

Answer:

a) $E(X) = 6.45$

b) $E(X^{2} )= 57.25$

c) $V(X) = 15.648$

d) E(3X + 2) = 21.35

e) $E(3X^{2} +2) = 173.75$

f) V(3X+2) = 140.832

g) E(X+1) = 7.45

h) V(X+1) = 15.648

Step-by-step explanation:

a) $E(X) = \sum xP(x)$

$E(X) = (1*0.05) + (2*0.10) + (4*0.35) + (8*0.40) + (16*0.10)\\E(X) = 6.45$

$E(X^{2} ) = (1^{2} *0.05) + (2^{2} *0.10) + (4^{2} *0.35) + (8^{2} *0.40) + (16^{2} *0.10)\\ E(X^{2} )= 57.25$

$V(X) = E(X^{2} ) - (E(X))^{2} \\V(X) = 57.25 - 6.45^{2} \\V(X) = 15.648$

$E(3X+2) = 3E(X) + 2\\E(3X+2) = (3*6.45) + 2 \\E(3X+2) = 21.35$

$E(3X^{2} +2) = 3E(X^{2} ) + 2\\E(3X^{2} +2) = (3*57.25) + 2 \\E(3X^{2} +2) = 173.75$

$V(3X+2) = 3^{2} V(X)\\V(3X+2) = 9*15.648\\V(3X+2) = 140.832$

$E(X+1) = E(X) + 1\\E(X+1) = 6.45 + 1\\E(X+1) =7.45$

$V(X+1) = 1^{2} V(X)\\V(X+1) = 15.648$

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Sholpan [36]

Answer:

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Step-by-step explanation:

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KatRina [158]

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3 years ago

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