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3 years ago

What value of x will make parallelogram ABCD a rhombus?

Mathematics

2 answers:

Vesnalui [34]3 years ago

6 0

Value of x=34degree will make parallelogram ABCD a rhombus

PilotLPTM [1.2K]3 years ago

6 0

Answer:34

Step-by-step explanation:

i got it right

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In AABC, MZA = 16°, mZB = 49°, and<br> a = 4. Find c to the nearest tenth.

zhannawk [14.2K]

Answer:

Step-by-step explanation:

The sum of angles in a triangle is 180°, so angle C is ...

C = 180° -A -B

C = 180° -16° -49° = 115°

The measure of side c can be found from the Law of Sines:

c/sin(C) = a/sin(A)

c = a·sin(C)/sin(A) = 4·sin(115°)/sin(16°)

c ≈ 13.2

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2 years ago

A rectangle has a length of 11 inches and a width of 8 inches whose sides are changing. The length is increasing by 4 in/sec and

Amanda [17]

Answer:

Step-by-step explanation:

5+4=9

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2 years ago

I need help with review #1-5

Ratling [72]

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3 years ago

PLEASE HELP Given: △KLM LM=12, m∠K=60°, m∠M=45° Find: Perimeter of △KLM.

worty [1.4K]

We have to find the perimeter of the triangle KLM.

We have been given that the length of the side LM=12, $m\angleK=60^\circ$ , and $m\angle M= 45^\circ$

Refer the attached image.

In a triangle sum of three angles should be $180^\circ$ .

So,

$m\angle K+m\angle L+m\angle M=180^\circ$

Plugging the values of angle K and angle M, we get:

$60^\circ+m\angle L+45^\circ=180^\circ$

So,

$m\angle L=180^\circ-105^\circ=75^\circ$

Now, that we have the measure of angle L, we will apply sine rule to find the length of the sides KL and KM.

Using the sine law for the triangle KLM, we get:

$\frac{sin K}{LM}=\frac{sin L}{KM}=\frac{sin M}{KL}$

Refer the image. Plugging the value of the sides of the triangle KLM and the angles of the triangle KLM, we get:

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}=\frac{sin 45^\circ}{x}$

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 75^\circ}{y}$

We get the value of 'y'

$y=\frac{sin 75^\circ}{sin 60^\circ} \times 12=\frac{0.9659}{0.866} \times 12=13.38$

So the length of the side KM is 13.38 units.

Now using,

$\frac {sin 60^\circ}{12}=\frac{sin 45^\circ}{x}$

We get the value of 'x'

$x=\frac{sin 45^\circ}{sin 60^\circ} \times 12=\frac{0.707}{0.866} \times 12=9.79$

So the length of the side KL is 9.79 units.

Now, to find the perimeter of the triangle KLM we need to sum up the length of the sides of the triangle KLM.

The perimeter of the triangle KLM $= KL+ LM + KM = 9.79 + 12 + 13.38 = 35.17$ units

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3 years ago

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The table shows the temperature (y) at different altitudes (x). This is a linear relationship. Find the y−intercept for this rel

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2 years ago