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3 years ago

Do Diffusion and Osmosis require energy? Explain please!?

1 answer:

8 0

Neither do.beacuse diffusion occurs due the random movement a substance's particals move from a higher concentration to a lower concentration down the concentration gradient.On the other hand osmosis is the movement of water molecules from a high water potential to a low water potential through a partially permeable membrane.thus no energy is required for them to do so.Active transport is a process that requires energy.

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Tar is hard to pour because it doesn’t flow easily

IgorC [24]

tar is very thick and viscous making it difficult to pour when cold which is why it's heated to extremely high temperatures when blacktop is being poured

6 0

3 years ago

Read 2 more answers

By definition, acceleration is (5 Points)

Dovator [93]

Acceleration is a change in speed and/or direction

Explanation:

The acceleration of an object is defined as the rate of change of velocity, mathematically:

$a=\frac{\Delta v}{\Delta t}$

where

$\Delta v$ is the change in velocity

$\Delta t$ is the time taken for the velocity of the object to change

We notice that velocity is a vector quantity, so it consists of:

- A magnitude, which is called speed

- A direction

Since acceleration is the rate of change in velocity, this means that the acceleration is non-zero whenever $\Delta v$ is non-zero, which means that either the speed AND/OR the direction of the velocity is changing.

For instance:

- For an object which is speeding up along a straight line, the speed is changing but the direction is not --> still, the object is accelerating

- For an object moving in a uniform circular motion, the speed is constant while the direction is changing --> still, the object is accelerating

So the correct answer is

a change in speed and/or direction

Learn more about acceleration:

brainly.com/question/9527152

brainly.com/question/11181826

brainly.com/question/2506873

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#LearnwithBrainly

6 0

3 years ago

Which of the following is TRUE regarding Softball?

Y_Kistochka [10]

Answer:

There are two popular forms of softball, distinguished by the type of pitch.

Explanation:

Softball refers to a kind of sports that is similar to baseball in terms of game play but softball is played with a larger ball. The game of softball was first introduced as an indoor game in Chicago, Illinois, United States of America in the year 1887. Also, the field for playing softball is relatively smaller than that of baseball and as such its game play is quite faster.

Some of the kits and paraphernalia used for playing softball are base, bat, softball, gloves, jerseys etc.

There are two (2) main types of softball game and these are;

I. Fast-pitch softball.

II. Slow-pitch softball.

Hence, the true statement regarding softball is that, there are two popular forms of softball, distinguished by the type of pitch.

7 0

3 years ago

Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x'(t) is its velocity, and x''

Lady_Fox [76]

Answer:

We know that the acceleration of the particle is defined as

$a(t)=\frac{dv}{dt}$

Since it is given that

$v(t)=\frac{5}{\sqrt{t}}\\\\\therefore a(t)=\frac{d(\frac{5}{\sqrt{t}})}{dt}\\\\a(t)=5\times \frac{dt^{-\frac{1}{2}}}{dt}\\\\=\frac{-5}{2}t^{\frac{-1}{2}-1}\\\\\therefore a(t)=x''(t)=\frac{-2.5}{t^{\frac{3}{2}}}$

Now by definition of velocity we have

$v(t)=\frac{dx(t)}{dt}\\\\\Rightarrow dx(t)=v(t)dt$

Integrating on both sides we get

$v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int v(t)dt$

Applying values we get

$v(t)=\frac{dx(t)}{dt}\\\\\int dx(t)=\int v(t)dt\\\\x(t)=\int \frac{5}{t^{\frac{1}{2}}}dt\\\\\therefore x(t)=\frac{5}{0.5}\int t^{-0.5}dt\\\\x(t)=10\sqrt{t}+c$