community group is planning the expansion of a square flower garden in the city park if each side of the original Garden is incr
1 answer:
4mm
The sides of the new garden can be represented by x+9. x is the original size and 9 is the added 9mm. Multiply the sides to get (x+9)(x+9) or
this will equal the area. Create an equation to solve for the unknown original length.
Take the square root of both sides
13=x+9
Subtract both sides by 9
4=x The original side was 4mm long
The sides of the new garden can be represented by x+9. x is the original size and 9 is the added 9mm. Multiply the sides to get (x+9)(x+9) or
this will equal the area. Create an equation to solve for the unknown original length.
Take the square root of both sides
13=x+9
Subtract both sides by 9
4=x The original side was 4mm long
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Answer:
If thrown up with the same speed, the ball will go highest in Mars, and also it would take the ball longest to reach the maximum and as well to return to the ground.
Step-by-step explanation:
Keep in mind that the gravity on Mars; surface is less (about just 38%) of the acceleration of gravity on Earth's surface. Then when we use the kinematic formulas:
the acceleration (which by the way is a negative number since acts opposite the initial velocity and displacement when we throw an object up on either planet.
Therefore, throwing the ball straight up makes the time for when the object stops going up and starts coming down (at the maximum height the object gets) the following:
When we use this to replace the 't" in the displacement formula, we et:
This tells us that the smaller the value of "g", the highest the ball will go (g is in the denominator so a small value makes the quotient larger)
And we can also answer the question about time, since given the same initial velocity , the smaller the value of "g", the larger the value for the time to reach the maximum, and similarly to reach the ground when coming back down, since the acceleration is smaller (will take longer in Mars to cover the same distance)