Okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t
now, find the half, set a(t)= half the original and solve for t
14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t
t=in(0.5)/(-0.1359)= (aprox) 5.1 days
Answer:
W = 12
L = 16
Step-by-step explanation:
Givens
L = L
W = 1/2 L + 4
Perimeter = 56
Formula
2L + 2W = Perimeter
Solution
Sustitute
2L + 2(1/2L + 4) = 56
2L + L + 8 = 56
3L + 8 = 56
3L + 8 - 8 = 56 - 8
3L = 48
3L/3 = 48/3
L = 16
W = 1/2 L + 4
W = 8 + 4
W = 12
Check
2L + 2W = 56
2*16 + 2*12 = 56
32 + 24 = 56
56 = 56 and it checks.
Answer:
do 8 times 4.2 then subtract the .6 to get to 33 hope this helped
I Think The answer is d I hope it helps Message Me if I’m wrong and I’ll change My answer and fix it for you
27 1/5 + 2/6
\\Convert to like fractions:
= 27 6/30 + 10/30
\\Add the fractions
= 27 16/30
\\Simplify by dividing by 2
= 27 8/15
Answer: 27 8/15
