Answer:
18 27 36 you just have to do your count byes for 9
All three series converge, so the answer is D.
The common ratios for each sequence are (I) -1/9, (II) -1/10, and (III) -1/3.
Consider a geometric sequence with the first term <em>a</em> and common ratio |<em>r</em>| < 1. Then the <em>n</em>-th partial sum (the sum of the first <em>n</em> terms) of the sequence is

Multiply both sides by <em>r</em> :

Subtract the latter sum from the first, which eliminates all but the first and last terms:

Solve for
:

Then as gets arbitrarily large, the term
will converge to 0, leaving us with

So the given series converge to
(I) -243/(1 + 1/9) = -2187/10
(II) -1.1/(1 + 1/10) = -1
(III) 27/(1 + 1/3) = 18
0.03 compare to 0.003
While comparing decimals we write the decimals one below the other according to the place value of each digits in place value chart
ones -- point -- Tenths -- Hundredths -- Thousandths
0 . 0 3
0 . 0 0 3
Now we compare each digit left to right. We have 3 in hundredths and 0 in hundredths place. 3 is greater
So 0.03 is greater than 0.003
0.03 > 0.003
Answer:
f(x) = x
Step-by-step explanation:
f(x) = |x| will give you V graph
f(x) = x will give you line graph (linear)
f(x) = x² will give you a curve graph