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Kay [80]
2 years ago
15

Solve for x if 7x =21 a. X=-3 b.x=14 c. =3 d. X= -14

Mathematics
1 answer:
vaieri [72.5K]2 years ago
5 0
I hope this helps you



7x÷7=21÷7



x=3
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Center: (10,-10)
vova2212 [387]

This is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

What is the ellipse?

The equation for an ellipse is typically written as x² a²  + y² b² = 1. x²  a² + y² b²  = 1. An ellipse with its origin at the center is defined by this equation. The ellipse is stretched further in both the horizontal and vertical directions if a > b, a > b, and if b > a, b > a, respectively.

The standard form of the equation of an ellipse with center (h, k)and major axis parallel to the x-axis is:

\frac{(x - h)^2}{a^2} + \frac{(y - k)^2}{b^2} = 1

where,

a > b

the length of the major axis is 2a

the coordinates of the vertices are (h±a,k)

the length of the minor axis is 2b

the coordinates of the co-vertices are (h,k±b)

the coordinates of the foci are (h±c,k),

where c² = a² − b².

so,

\frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1

Hence, this is the standard form equation \frac{(x - 10)^2}{100} + \frac{(y + 10)^2}{-100} = 1.

To learn more about ellipse, visit

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7 0
10 months ago
Evaluate how organizations can use one-sample hypothesis testing to determine if there are performance issues in the organizatio
Margarita [4]

Answer:

Organizations can use one-sample hypothesis test to determine if there are performance issues in many ways.

It can be applied to the performance of a sector, a machine, a product, an advertising campaing, etc.

For example, we can take the example of a machine. It may be claimed that a specific machine performs significantly worse than the average.

This average would be the population mean: the average performance of the machines of the same type or process.

Then, a sample of the performance of the machine in study is taken and the hypothesis test can be performed to test the claim that this machine performs significantly worse.

Step-by-step explanation:

For example, we have an historic performance for this type of machine of 100 units a day. The machine A in study is sampled 14 days and have a performance of 92 units a day, with a sample standard deviation of 12 units/day. We have to test the claim that the machine A makes less units per day than the average.

Then, the null and alternative hypothesis are:

H_0: \mu=100\\\\H_a:\mu< 100

The significance level is 0.05.

The sample has a size n=14.

The sample mean is M=92.

As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=12.

The estimated standard error of the mean is computed using the formula:

s_M=\dfrac{s}{\sqrt{n}}=\dfrac{12}{\sqrt{14}}=3.2071

Then, we can calculate the t-statistic as:

t=\dfrac{M-\mu}{s/\sqrt{n}}=\dfrac{92-100}{3.2071}=\dfrac{-8}{3.2071}=-2.4944

The degrees of freedom for this sample size are:

df=n-1=14-1=13

This test is a left-tailed test, with 13 degrees of freedom and t=-2.4944, so the P-value for this test is calculated as (using a t-table):

P-value=P(t

As the P-value (0.0134) is smaller than the significance level (0.05), the effect is  significant.

The null hypothesis is rejected.

There is enough evidence to support the claim that machine A produces significantly less units per day than the average.

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3 years ago
What’s the gcf of 89 and 64
sergij07 [2.7K]
The greatest common factor is 1
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Answer:

any picture or can you tell us what the amounts stand for?

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2 years ago
Please help! This is timed
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I think the answer is C 1 2/3
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