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OLga [1]
3 years ago
7

In △ABC, m∠A=16°, m∠B=49°, and a=4. Find c to the nearest tenth.

Mathematics
1 answer:
mars1129 [50]3 years ago
8 0

Answer:

c=13.2 units

Step-by-step explanation:

step 1

Find the measure of angle C

Remember that the sum of the internal angles of a triangle must be equal to 180 degrees

so

A+B+C=180°

substitute the given values

16°+49°+C=180°

65°+C=180°

C=180°-65°=115°

step 2

Find the measure of c

Applying the law of sines

c/sin(C)=a/sin(A)

substitute the given values and solve for c

c/sin(115°)=4/sin(16°)

c=4(sin(115°))/sin(16°)

c=13.2 units

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Given f(x) = x^3 + kx + 2, and x + 1 is a factor of f(x), then what is the value of <br> k?
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Hi! Algebra two question, rational exponents.
ivanzaharov [21]

Simplifying \left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}} we get \left(x+4y\right)}

Step-by-step explanation:

We need to simplify:

\left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}}

For solving, we will first simplify the terms inside the exponent and then solve exponent

First Solving: \left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}

Using the formula: (a^2+2ab+b^2)=(a+b)^2

\left(x^2+8xy+16y^2\right)}.\left(x+4y\right)}\\\left((x)^2+2(x)(4y)+(4y)^2\right)}.\left(x+4y\right)}\\\left(x+4y\right)^2}.\left(x+4y\right)}

Using exponent rule:

a^m.a^n=a^{m+n}

\left(x+4y\right)^{2+1}}\\\left(x+4y\right)^3}

Now,

(\left(x+4y\right)^3})^{\frac{1}{3}}\\Simplifiying:\\\left(x+4y\right)}^{\frac{3}{3}}\\\left(x+4y\right)}

So, simplifying \left(x^2+8xy+16y^2\right)^{\frac{1}{3}}.\left(x+4y\right)^{\frac{1}{3}} we get \left(x+4y\right)}

Keywords: Solving Rational exponents:

Learn more about Solving Rational exponents at:

  • brainly.com/question/13174254
  • brainly.com/question/13174255
  • brainly.com/question/5639299
  • brainly.com/question/729447

#learnwithBrainly

4 0
4 years ago
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