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2 years ago

Your vote does matter.TRUEFALSE

Geography

2 answers:

podryga [215]2 years ago

6 0

True. Everyone's vote in the election process counts!

tiny-mole [99]2 years ago

6 0

True because it counts ure vote with all the other votes and it makes the probablity of winning is more. So the every vote matters.
Count me the brainliest plse

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2<br> List the 8 types of energy (SCREAM TG) *<br> (4 Points)<br> [<br> Enter your answer<br> I

KonstantinChe [14]

Answer:

Gravitational energy, potential energy, Radiant energy, sound energy, light energy, nuclear power energy, Mechanics energy, Electricity.

Explanation:

6 0

2 years ago

Why are fossil fuels used so much today?

stealth61 [152]

Answer:

the reason fossil fuels are so readily used is because they are readily available. countries in the middle east, as well as russia, the us and a few south american countries have large oil reserves that are currently used to supply the world's demand for energyy

hope this helps lol

and brainiest would be appreciated :P

8 0

2 years ago

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What is the value of X6? <br><br> Show the solution.

wariber [46]

Answer : The value of $x_6$ is $\sqrt{7}$ .

Explanation :

As we are given 6 right angled triangle in the given figure.

First we have to calculate the value of $x_1$ .

Using Pythagoras theorem in triangle 1 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_1)^2=(1)^2+(1)^2$

$x_1=\sqrt{(1)^2+(1)^2}$

$x_1=\sqrt{2}$

Now we have to calculate the value of $x_2$ .

Using Pythagoras theorem in triangle 2 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_2)^2=(1)^2+(X_1)^2$

$(x_2)^2=(1)^2+(\sqrt{2})^2$

$x_2=\sqrt{(1)^2+(\sqrt{2})^2}$

$x_2=\sqrt{3}$

Now we have to calculate the value of $x_3$ .

Using Pythagoras theorem in triangle 3 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_3)^2=(1)^2+(X_2)^2$

$(x_3)^2=(1)^2+(\sqrt{3})^2$

$x_3=\sqrt{(1)^2+(\sqrt{3})^2}$

$x_3=\sqrt{4}$

Now we have to calculate the value of $x_4$ .

Using Pythagoras theorem in triangle 4 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_4)^2=(1)^2+(X_3)^2$

$(x_4)^2=(1)^2+(\sqrt{4})^2$

$x_4=\sqrt{(1)^2+(\sqrt{4})^2}$

$x_4=\sqrt{5}$

Now we have to calculate the value of $x_5$ .

Using Pythagoras theorem in triangle 5 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_5)^2=(1)^2+(X_4)^2$

$(x_5)^2=(1)^2+(\sqrt{5})^2$

$x_5=\sqrt{(1)^2+(\sqrt{5})^2}$

$x_5=\sqrt{6}$

Now we have to calculate the value of $x_6$ .

Using Pythagoras theorem in triangle 6 :

$(Hypotenuse)^2=(Perpendicular)^2+(Base)^2$

$(x_6)^2=(1)^2+(X_5)^2$

$(x_6)^2=(1)^2+(\sqrt{6})^2$

$x_6=\sqrt{(1)^2+(\sqrt{6})^2}$

$x_6=\sqrt{7}$

Therefore, the value of $x_6$ is $\sqrt{7}$ .

5 0

2 years ago

26points geometry I need help

WARRIOR [948]

Add eight every time do
27+8=35 then 35+8=43
so 35 then 43

6 0

2 years ago

Define the terms of arable land use

NikAS [45]

Explanation:

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2 years ago

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