8 39/40
=8+39/40
=8•40/40+39/40
=320/40+39/40
=320+39/40
=359/40
=8.975
The answer is 8 39/40=8.975
Answer:
Step-by-step explanation:
(0, -1) (3,3)
(3 + 1)/(3 - 0) = 4/3
y + 1 = 4/3(x - 0)
y + 1 = 4/3x - 0
y = 4/3x - 1
answer is A
Complete question is:
Seventy million pounds of trout are grown in the U.S. every year. Farm-raised trout contain an average of 32 grams of fat per pound, with a standard deviation of 7 grams of fat per pound. A random sample of 34 farm-raised trout is selected. The mean fat content for the sample is 29.7 grams per pound. Find the probability of observing a sample mean of 29.7 grams of fat per pound or less in a random sample of 34 farm-raised trout. Carry your intermediate computations to at least four decimal places. Round your answer to at least three decimal places.
Answer:
Probability = 0.0277
Step-by-step explanation:
We are given;
Mean: μ = 32
Standard deviation;σ = 7
Random sample number; n = 34
To solve this question, we would use the equation z = (x - μ)/(σ/√n) to find the z value that corresponds to 29.7 grams of fat.
Thus;
z = (29.7 - 32)/(7/√34)
Thus, z = -2.3/1.200490096
z = -1.9159
From the standard z table and confirming with z-calculator, the probability is 0.0277
Thus, the probability to select 34 fish whose average grams of fat per pound is less than 29.7 = 0.0277
<span>21-3y=36-6y +3y
21 = 36 - 3y -36
-36+21 = -3y
- 15 = - 3y ÷ -3
5 = y
Choice: B
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