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Korvikt [17]
4 years ago
14

Seth traveled 1 mile in 57.1 seconds. About how fast does Seth travel in miles per hour?

Mathematics
2 answers:
jeka57 [31]4 years ago
7 0
So, 60/57.1 = 1.05 
1*1.05 = 1.05
1.05 * 60 = 63 mph
Hope this helps
Brainliest Please!
a_sh-v [17]4 years ago
4 0
63.0472854642 hope that helps.
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Hamzah's soccer team is trying to raise $620 to travel to a tournament in Florida, so they decided to host a pancake breakfast.
Kobotan [32]

Answer:

31 people

Step-by-step explanation:

Hamzah soccer team is trying to raise the amount of $620 to travel to a tournament in Florida

The soccer team decide to organise a pancake breakfast

Each person that attends the breakfast must pay $20

Therefore the amount of people needed to attend the breakfast to raise $620 can be calculated as follows

= 620/20

= 31

Hence 31 people need to be in attendance inorder to raise $620

5 0
3 years ago
SOS i need helppp!! i'm not good at math just reading and science!!!
Viktor [21]

I got 45 for x and 135 for z.

X and 3x are supplementary (they equal 180) x+3x=180 — 45+3(45)=180

Then x and z are also supplementary x+z=180 — 45+z=180

(45-45)+z=180-45

Z=135

Sorry if this is wrong. I did my best, hope it helps

7 0
3 years ago
The diagram shows a Convex Polygon, what is the value of A?
Hatshy [7]

Answer:

I think it's 40 hopes this help

8 0
3 years ago
The ideal width of a certain conveyor belt for a manufacturing plant is 50 in. Conveyor belts can vary from the ideal width by a
Gennadij [26K]
<h3><u>Answer:</u></h3>

The answer is:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

<h3><u>Step-by-step explanation:</u></h3>

The ideal  width of a certain conveyor belt for a manufacturing plant is 50 in.

Conveyor belts can vary from the ideal width by at most 7/32 in.

i.e. the absolute change in the width has to be less than or equal to 7/32 in. and it can't exceed more than that.

That is if it will decrease than the  the acceptable width for the conveyor belt is represented by the expression;

|x-50|\leq \dfrac{7}{32}

Also on solving it we get:

\dfrac{-7}{32}\leq x-50\leq \dfrac{7}{32}\\\\\\50-\dfrac{7}{2}\leq x\leq 50+\dfrac{7}{2}\\\\49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

Hence, the correct choices are:

|x-50|\leq \dfrac{7}{32}

49\dfrac{25}{32}\leq x\leq 50\dfrac{7}{32}

7 0
3 years ago
I have 7 questions but I will give the person who answers all my points :)
vovikov84 [41]
<h2>Answers:</h2><h2></h2><h2>1. 2 x 3 x 3 x 3</h2><h2>2. 3.4</h2><h2>3. 0.6 , 60%</h2><h2>4. 125</h2><h2>5. 1 61/90 or 151/90</h2><h2>6. 89.907</h2><h2>7. 1/3</h2><h2></h2><h2></h2><h2>Hope this helps!!</h2>

6 0
3 years ago
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