What does 805 tens equal

Help ASAP, question below, 20 points

Talja [164]

Answer:

1 more lawn per hour

Step-by-step explanation:

Brian mows one lawn every hour while logan takes 4 hours to mow 2

Brian:

Hr 1 1 Lawn

Hr 2 2 Lawn

Hr 3 3 Lawn

Hr 4 4 Lawn

Logan:

Hr 1 2 Lawn

Hr 2 4 Lawn

Hr 3 6 Lawn

Hr 4 8 Lawn

4 0

2 years ago

In the Alt J song, In Cold

Arlecino [84]

Answer:

kjjhgyufg

Step-by-step explanation:

7 0

2 years ago

Sam used wire fencing to form a border around a circular region in his back yard. If the diameter of the circular region was 16

Dennis_Churaev [7]

The total length of the border = 50.2 yards

Step-by-step explanation:

Step 1 :

Given,

Diameter of the circular region = 16 yards

We need to compute the total length of the border.

Step 2 :

The total length of the border can be obtained by computing circumference of the region with the given diameter

Circumference = 2(pi)(r)

where r is the radius

here diameter = 16, so radius = 8 yards

Hence circumference = 2 (3.14) 8 = 50.24 yards

Step 3 :

Answer :

The total length of given border = 50.2 yards (rounded off to nearest 10th)

5 0

2 years ago

Solve each of the following equations.<br>(4b + 11)(3b - 7) = 0

Andrej [43]

Answer:

4b = 4(11/4)

3b = 3(7/3)

3 0

2 years ago

Trials in an experiment with a polygraph include 98 results that include 24 cases of wrong results and 74 cases of correct resul

madreJ [45]

Answer:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

Step-by-step explanation:

Data given and notation

n=98 represent the random sample taken

X=74 represent the number of cases correct

$\hat p=\frac{74}{98}=0.755$ estimated proportion of successes

$p_o=0.8$ is the value that we want to test

$\alpha=0.05$ represent the significance level

Confidence=95% or 0.95

z would represent the statistic (variable of interest)

$p_v$ represent the p value (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to test the claim that the true proportion of successes is less than 0.8.:

Null hypothesis: $p\geq 0.8$

Alternative hypothesis: $p < 0.8$

When we conduct a proportion test we need to use the z statisitc, and the is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

The One-Sample Proportion Test is used to assess whether a population proportion $\hat p$ is significantly different from a hypothesized value $p_o$ .

Calculate the statistic

Since we have all the info requires we can replace in formula (1) like this:

$z=\frac{0.755 -0.8}{\sqrt{\frac{0.8(1-0.8)}{98}}}=-1.114$

Statistical decision

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.

The significance level provided $\alpha=0.05$ . The next step would be calculate the p value for this test.

Since is a left tailed test the p value would be:

$p_v =P(z$

So the p value obtained was a very high value and using the significance level given $\alpha=0.05$ we have $p_v>\alpha$ so we can conclude that we have enough evidence to FAIL to reject the null hypothesis, and we can said that at 5% of significance the proportion of successes is not significantly less than 0.8 or 80%

5 0

2 years ago