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nikklg [1K]
3 years ago
11

( CORRECT ANSWER GETS BRAINLIEST AND FULL RATINGS !!!)

Mathematics
1 answer:
ozzi3 years ago
6 0

Answer:

a . 1/13      

Step-by-step explanation:

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Can someone please help i really need to ace this <br><br> x = ___ degrees
lord [1]

Answer:pretty sure its 10 degrees

Step-by-step explanation:

all tris add up to 180, and this one is a right angle so you know you have 90 deg, 80 degrees. 90+80=170; 180-170=10

6 0
3 years ago
Help me please. thank you..
11111nata11111 [884]
A because you have to make 16/32 into 1/2, and 4/16 is not a half.
4 0
3 years ago
Read 2 more answers
I'm having trouble with #2. I've got it down to the part where it would be the integral of 5cos^3(pheta)/sin(pheta). I'm not sur
Butoxors [25]
\displaystyle\int\frac{\sqrt{25-x^2}}x\,\mathrm dx

Setting x=5\sin\theta, you have \mathrm dx=5\cos\theta\,\mathrm d\theta. Then the integral becomes

\displaystyle\int\frac{\sqrt{25-(5\sin\theta)^2}}{5\sin\theta}5\cos\theta\,\mathrm d\theta
\displaystyle\int\sqrt{25-25\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{1-\sin^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

Now, \sqrt{x^2}=|x| in general. But since we want our substitution x=5\sin\theta to be invertible, we are tacitly assuming that we're working over a restricted domain. In particular, this means \theta=\sin^{-1}\dfrac x5, which implies that \left|\dfrac x5\right|\le1, or equivalently that |\theta|\le\dfrac\pi2. Over this domain, \cos\theta\ge0, so \sqrt{\cos^2\theta}=|\cos\theta|=\cos\theta.

Long story short, this allows us to go from

\displaystyle5\int\sqrt{\cos^2\theta}\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta

to

\displaystyle5\int\cos\theta\dfrac{\cos\theta}{\sin\theta}\,\mathrm d\theta
\displaystyle5\int\dfrac{\cos^2\theta}{\sin\theta}\,\mathrm d\theta

Computing the remaining integral isn't difficult. Expand the numerator with the Pythagorean identity to get

\dfrac{\cos^2\theta}{\sin\theta}=\dfrac{1-\sin^2\theta}{\sin\theta}=\csc\theta-\sin\theta

Then integrate term-by-term to get

\displaystyle5\left(\int\csc\theta\,\mathrm d\theta-\int\sin\theta\,\mathrm d\theta\right)
=-5\ln|\csc\theta+\cot\theta|+\cos\theta+C

Now undo the substitution to get the antiderivative back in terms of x.

=-5\ln\left|\csc\left(\sin^{-1}\dfrac x5\right)+\cot\left(\sin^{-1}\dfrac x5\right)\right|+\cos\left(\sin^{-1}\dfrac x5\right)+C

and using basic trigonometric properties (e.g. Pythagorean theorem) this reduces to

=-5\ln\left|\dfrac{5+\sqrt{25-x^2}}x\right|+\sqrt{25-x^2}+C
4 0
3 years ago
Read 2 more answers
Encouraged by his investment, Joseph decides to open another CD account. This time, he deposits $1000 and plans to leave it unto
Lilit [14]

Answer:

1,113.87

Step-by-step explanation: Ps it was a joke man

5 0
3 years ago
the equation y equals 0.25 x describes a proportional relationship between X and Y what is the constant of proportionality
Fittoniya [83]
The constant of proportionality is for every 1 x, there is 0.25 y. y = 0.25, and on a graph, x is always the "1." Since x is worth 1, y must be worth 0.25.
4 0
3 years ago
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