Answer:
Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
Step-by-step explanation:
In order to determine if the poster will lie flat in the box or not, we will determine the length of the sides of the poster and the box, if the length of the side of the square poster is smaller than that of the box, it will lie flat. This is calculated as follows:
Area of poster = 4 square feet
Area of poster = (Length)²
4 = (Length)²
∴ Length = √(4)
Length of poster = 2 Ft
Volume of box = 14 cubic feet
Volume of box = (Length)³
14 = (Length)³
∴ Length = ∛(14)
Length = 2.41 Ft
∴ Length of sides of poster = 2 Ft
Length of sides of box = 2.41 Ft
Since the box has a longer side than the poster, the poster will lie flat when placed in the box.
The equation: 6r-3=45
6r=48
Answer: r=8
Answer:
5(a+4)
Step-by-step explanation:
expression is equivalent to 5a+20
To get the equivalent expression we need to factor the given expression
5a+ 20
5a can be written as 5 * a
20 can be written as 5*2*2
WE can see that common factor is 5 for both 5a and 20
So GCF is 5
Now we factor out GCF 5
WE put 5 outside and write all the left of factors inside the parenthesis
5a +20
5 (a+2*2)
5(a+4)
Answer: 
Step-by-step explanation:
Answer:
45 is um 9x+xy-4y
Step-by-step explanation:
I did it it was a simplify type thing
