Question

Please help! Just with Part B...

Answer 1

Answer:

a) Number of calories burned in $x$ hours of cycling $600x$ and Number of calories burned in $y$ hours of Swimming is $400y$.

b)The equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is $6x+4y=160$.

Step-by-step explanation:

Given:

5 pounds of body fat = 16000 calories

Number of calories burn in 1 hour of cycling = 600

Number of calories burn in 1 hour of swimming = 400

Part a:

We need to find number of calories will Carol burn in $x$ hours of cycling and number of calories will Carol burn in $y$ hours of swimming.

Solution:

Now we know that;

1 hr of cycling = 600 calories burned

$x$ hr of cycling = Number of calories burned in $x$ hours of cycling.

By using Unitary method we get;

Number of calories burned in $x$ hours of cycling = $600x$

Also we know that;

1 hr of swimming= 400 calories burned

$y$ hr of swimming = Number of calories burned in $y$ hours of swimming.

By using Unitary method we get;

Number of calories burned in $y$ hours of Swimming = $400y$

Hence Number of calories burned in $x$ hours of cycling $600x$ and Number of calories burned in $y$ hours of Swimming is $400y$

Part b:

We need to write equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds.

Solution:

Now given;

5 pounds = 16000 calories.

So we can say that;

Total number of calories to be burn is equal to sum of Number of calories burned in $x$ hours of cycling  and Number of calories burned in $y$ hours of Swimming.

framing in equation form we get;

$600x+400y=16000$

Now dividing both side by 100 we get;

$\frac{600x}{100}+\frac{400y}{100}=\frac{16000}{100}\\\\6x+4y=160$

Hence the equation in general form that relates number of hours of cycling and swimming carols needs to perform to loose 5 pounds is $6x+4y=160$.