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Mrrafil [7]
3 years ago
10

PLEASE HELP 50 POINTS!! 11th grade geometry

Geography
2 answers:
d1i1m1o1n [39]3 years ago
6 0

Since, AD ≅ BC, ∠BCD ≅ ∠ADC and segment CD ≅ DC, △ADC ≅ △BCD by SAS. Therefore, based on CPCTC, DE ≅ CE.

Explanation:

  • We are given AD ≅ BC and ∠BCD ≅ ∠ADC.
  • The segment CD is common for △ADC and △BCD.
  • This means BCD and ADC are isosceles triangles.  
  • Therefore, we can say that △ADC ≅ △BCD by SAS.
  • Because of CPCTC, segment DE is congruent to segment CE.
  • Hence, based on the isosceles triangle theorem, DE ≅ CE.

goldfiish [28.3K]3 years ago
6 0

Answer:

DE ≅ CE

Explanation:

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