Question

1. Find the distance between (4,1) and (2,6)

Answer 1

Answer:

d = √29

Explanation:

$d=\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}\\\\x_1 =4\\y_1 =1\\x_2=2\\y_2 =6\\\\d=\sqrt{\left(2-4\right)^2+\left(6-1\right)^2}\\\\d = \sqrt{(-2)^2+(5)^2}\\ \\d = \sqrt{4+25}\\ \\d = \sqrt{29}$

Answer 2

(2,5) is the distance between those points