Please anyone help me with this please!!?

How would you solve this?

finlep [7]

Answer:the probability that a pensioner catches a flu is 0.3 or $\frac{3}{10}$

Step-by-step explanation:

Data:

a) Pensioners who have had a flu jab = $\frac{3}{5}$

b) Pensioners who did not had a flu jab = 1 - $\frac{3}{5}$ = $\frac{2}{5}$

For the first pair of arrows: a is the probability of the upper arrow and b is the probability of the lower arrow.

If pensioner have had a flu jab, the probability of catching flu is $\frac{1}{30}$

Data:

c) Catching flu = $\frac{1}{30}$

d) Not catching flu = 1 - $\frac{1}{30}$ = $\frac{29}{30}$

The second pair of arrows on the top: Top arrow is c and bottom arrow is d

If pensioner did not have a flu jab, the probability of catching flu is $\frac{7}{10}$

Data:

e) Catching flu = $\frac{7}{10}$

f) Not catching flu = 1 - $\frac{7}{10}$ = $\frac{3}{10}$

The second pair of arrows on the bottom: Top arrow is e and bottom arrow is f.

Q) Probability pensioner catches a flu

P(catches the flu given that he had the flu jab) + P(catches the flu given that he did not have the flu jab)

( $\frac{3}{5}$ x $\frac{1}{30}$ ) + ( $\frac{2}{5}$ x $\frac{7}{10}$ )

= 0.02 + 0.28

= 0.3

Therefore, the probability that a pensioner catches a flu is 0.3 or $\frac{3}{10}$

Keyword: Probability

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5 0

3 years ago

Need help with this problem on homework

mylen [45]

The answer is 2x - 2

5 0

3 years ago

ABCD is a rhombus. If m<1=122, then what is the measure of <2 and <3

Svetach [21]

M < 2 will be 180 - 122 = 58 degrees

< 3 is opposite < 1 so it will be = 122 degrees

4 0

3 years ago

18 points - Qu. If 16 whole numbers factor into 120. You will see how 32 whole numbers factor into 1200 what does the same princ

alexandr402 [8]

Explanation:

Your premise and conclusion are both incorrect.

120 has the prime factorization ...

120 = 2³ × 3 × 5

The exponents of the prime factors are {3, 1, 1}. The number of divisors of 120 is the product of the increments of these numbers: (3+1)(1+1)(1+1) = 4·2·2 = 16.

120 has 16 natural-number divisors

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1200 has the same prime factor and two more: 2·5, so the factorization is ...

1200 = 2⁴ × 3 × 5²

These exponents are {4, 1, 2} and the product of their increments is 5·2·3 = 30.

1200 has 30 natural-number divisors.

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When a number is multiplied by 2, its number of natural-number divisors will be (n+1)/n times the previous number of divisors, where n is the increment of the exponent of 2 that is a factor of the original number.

For 120, 2^3 is the power of 2 that is a factor. So, multiplying the number by 2 multiplies the number of divisors by (4+1)/4 = 5/4.

240 will have 20 divisors versus the 16 that 120 has.

Likewise, multiplying this number (240) by 5 will multiply its number of divisors by (2+1)/(1+1) = 3/2, where 1 is the power of 5 that is a factor of 240.

1200 will have 20(3/2) = 30 divisors, versus the 20 that 240 has, or the 16 that 120 has.

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Summary

The number of divisors of an integer is the product of the increments of the exponents of its prime factors.

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For reference

Here are the divisors of 120:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Here are the divisors of 240:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 30, 40, 48, 60, 80, 120, 240

Here are the divisors of 1200:

1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 16, 20, 24, 25, 30, 40, 48, 50, 60, 75, 80, 100, 120, 150, 200, 240, 300, 400, 600, 1200