12:00 will have both hands pointing up
12:30 will have the straight line at the half past part but it will not be exactly on the 12
3:45 it will be past the 3 and exactly on 45 so it will not work
And 6:00 will be a straight line as one hand will be at the 12 and and it will be straight on the 6 as it is on the hour so the answer is d
Answer:
x=5
Step-by-step explanation:
We can use the Triangle Angel Bisector Theorem
AB 2x-1
----------= --------------
AC 3x
9 2x-1
----------= --------------
15 3x
Using cross products
3x*9 = 15*(2x-1)
Distribute
27x = 30x-15
Subtract 30x from each side
27x-30x = 30x-30x-15
-3x = -15
Divide by -3
-3x/-3 =-15/-3
x =5
Constants : 1 (the only constant term is 2)
Variables : 2 (x and y)
Terms : 3 ( x, y and 2)
Degree of term : 1
Answer:
m = 5
Step-by-step explanation:
.........................
Mostly collect like terms
use associative property which is
(a+b)+c=a+(b+c)
and remember that:
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
you can only add like terms( like terms are terms that are same name like x or y are differnt, and like terms have same power exg x^2 and x^3 and x^1/2 and such
so first one
3b+11c-4c-c
since they are all c except for the first one term, just assign a number for each so it simplifies to c times(11-1)+b(3-4)=c(10-1b=10c-b or
you just use a general rule
x+x=2x
x^2+x^2=2x^2
3xy4xy=7xy
3x+4x^2=3x+4x^2
second one9a-1+8c-8a+c
group like terms
(9a-8a)+(8c+c)-1=(a)+(9c)-1=a+9c-1
12c+5a+7-13c+4a
group like terms(12c-13c)+(5a+4a)+7
add like terms
-c+9a+7
the solution is 9a-c+7
-15-6c+3b-6c+9-2b
group like terms
(-15+9)+(-6c-6c)+(3b-2b)
-6+(-12c)+b=b-6-12c
the answers are:
10c-b
a+9c-1
9a-c+7
b-12c-6
