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vesna_86 [32]
2 years ago
11

You might need: Calculator Problem Zane is a dangerous fellow who likes to go rock climbing in active volcanoes. One time while

inside a volcano, he heard some rumbling, so he decided to climb up out of there as quickly as he could. He climbed up at a rate of 44 meters per second. After 33 seconds, he was 1313 meters below the edge of the volcano. How far was Zane below the edge of the volcano when he started climbing? How long did it take Zane to reach the edge of the volcano?
Mathematics
2 answers:
Ksenya-84 [330]2 years ago
7 0

Zane climb up in 33 seconds

44•33 = 1452 m.

so, Zane start from 1313 + 1452 = 2765 m below the edge.

to reach the edge with constant speed, Zane need 2765/44 = 62.84 seconds

we can round it to 63 seconds

Lesechka [4]2 years ago
6 0

Answer: Zane was 25 meters below the edge of the volcano when he started and he took 6.25 seconds to reach the edge of volcano.

Step-by-step explanation:

Since wee have given that

Speed at which he climb up = 4 meters per second

After 3 seconds, he was 13 meters below the edge of the volcano.

When he started climbing, Position of him below the edge of the volcano is given by

3\times 4+13\\\\=12+13\\\\=25\ meters

Time taken by Zane to reach the edge of the volcano is given by

=\dfrac{Distance}{Speed}\\\\=\dfrac{25}{4}\\\\=6.25\ seconds

Hence, Zane was 25 meters below the edge of the volcano when he started and he took 6.25 seconds to reach the edge of volcano.

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The tower is 61.65 meters tall.

<u>SOLUTION: </u>

Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.  

At the same time, a nearby tower casts a shadow that is 36.25 m long.  

We have to find height of the tower.  

Now, we know that,

2.5 \mathrm{m} \text { tall } \rightarrow 1.47 \text { long shadow }

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This can be written as,

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