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FinnZ [79.3K]
2 years ago
12

1.2÷0.375−0.2/6 4/25 ÷15 2/5 +0.8 = 0.016÷0.12+0.7/x pls solve for x with explaination

Mathematics
1 answer:
masha68 [24]2 years ago
6 0

The value of x is 0.1810

Step-by-step explanation:

Given the equation as;

1.2÷0.375 - 0.2/6 * 4/25 ÷ 15 2/5 +0.8 = 0.016 ÷ 0.12 +0.7/x

This can be written as;

1.2÷0.375-0.4/75÷77/5+0.8=0.016÷0.12+0.7/x

Apply BODMAS style (Brackets, Of, Division,Multiplication,Addition and Subtraction) where in this case you start with division

(1.2÷0.375)-(0.4÷75) ÷ 77/5 +0.8 = (0.016÷0.12) +0.7/x

3.2 - 0.00533 ÷ 15.4 +0.8 =0.133+0.7/x

3.2-0.0003461+0.8=0.133+0.7/x---------------apply addition

3.2+0.8 -0.0003461-0.133=0.7/x

4-0.0003461-0.133=0.7/x

3.867=0.7/x

0.7/3.867=x

0.1810=x

Learn More

https://brainly.in/question/3982019

https://brainly.in/question/11097160

Keywords : operations, BODMAS rule

#LearnwithBrainly

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6 0
3 years ago
<img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B28%20%7D%20%20%2B%20%20%5Csqrt%7B343%7D%20%20%5Cdiv%202%20%5Csqrt%7B63%20%7D%20"
Nadusha1986 [10]

Answer:

Step-by-step explanation:

sqrt(28): sqrt(4*7)

sqrt(4) = 2;

sqrt28)=2*sqrt(7)

sqrt(343): sqrt(7 * 7 * 7) = 7 * sqrt(7)

Note: the rule is if you have 3 equal primes under the root sign, you leave one, you throw one away, and you put one outside the root sign.

2 sqrt(63) = 2 sqrt(3*3*7)  The above rule gets modified to throw 1 three away and take the other one outside the root sign.

2sqrt(63) = 2*3 sqrt(7)

Numerator: 2*sqrt(7) + 7sqrt(7) = 9sqrt(7)

9sqrt(7)

======

6 sqrt(7)

3/2

Note without brackets I cannot be certain that I have interpreted this correctly. The division only apply to sqrt(343) / 2 sqrt(63). If this is so please leave a note.

7 0
3 years ago
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