1.2÷0.375−0.2/6 4/25 ÷15 2/5 +0.8 = 0.016÷0.12+0.7/x pls solve for x with explaination
1 answer:
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Answer:
The degrees of freedom are given by:
And the p value would be:
If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change
Step-by-step explanation:
Information given
represent the sample mean
represent the sample standard deviation
sample size
represent the value to verify
z would represent the statistic
represent the p value
Hypothesis to test
We want to check if the true mean is at most 360 seconds, the system of hypothesis would be:
Null hypothesis:
Alternative hypothesis:
The statistic for this case would be given by:
(1)
We can replace in formula (1) the info given like this:
The degrees of freedom are given by:
And the p value would be:
If we use a 5% of significance level we have enough evidence to reject the null hypothesis and we can conclude that the true mean is significantly higher than 360 second or 6 minutes. We need to be careful since if we use a significance level of 1% the result change